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3 years ago

As the number of electrons added to the same principal energy level increases, atomic size generally

2 answers:

8 0

As the number of electrons added to the same principal energy level increases, atomic size generally A. increases.

Because as you add energy levels, the electrons are drawn to the nucleus of the atoms giving them a lesser charge. Thus its atomic size also increases.

aliya0001 [1]3 years ago

6 0

increases electrons form a shell around the nucleaus making it larger

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Q- 30. The number of grams of solute

pochemuha

Answer:

Mass by mass

Explanation:

Because it's telling only about mass in grams

6 0

3 years ago

Two atoms that are isotopes of one another must have the same number of what? Electrons, All Particles, Protons, or Neutrons

emmainna [20.7K]

atoms are made of 3 types of sub atomic particles; neutrons, protons and electrons

atomic number is the number of protons which is characteristic for the element. Atoms of the same element have the same number of protons.

mass number is the sum of the neutrons and protons.

Isotopes are atoms of the same element with different mass numbers. since they are the same element number of protons are the same but number of neutrons vary.

therefore 2 isotopes are of the same element so they have the same number of protons.

5 0

3 years ago

Read 2 more answers

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

3 years ago

Who can tell me the half reaction about cucumber battery

xeze [42]

I've prepared some analysis and cucumbers do have many comparable properties to potatoes, tomatoes, and lemons, all of which I know do work. So I would presume that cucumbers would also work. I would recommend trying it yourself to perceive. I'd love to hear the outcomes of your experiment. ;)

6 0

3 years ago

An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm

frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

xA= 0.34, yA= 0.55

ii) 0.50 = 0.55 nv + 0.34 nL

Therefore, nV = 0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii) ρA= 0.791 g/cm3 and, ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0

3 years ago