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zmey [24]
3 years ago
5

As the number of electrons added to the same principal energy level increases, atomic size generally

Chemistry
2 answers:
3241004551 [841]3 years ago
8 0
<span>As the number of electrons added to the same principal energy level increases, atomic size generally A. increases.
</span>
<span>Because as you add energy levels, the electrons are drawn to the nucleus of the atoms giving them a lesser charge. Thus its atomic size also increases. </span>

aliya0001 [1]3 years ago
6 0

increases electrons form a shell around the nucleaus making it larger

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3 years ago
Draw the best Lewis structure for NH3 by filling in the bonds, lone pairs, and formal charges. (Assign bonds, lone pairs, radica
kiruha [24]

Answer :  The Lewis-dot structure of NH_3 is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, NH_3

As we know that hydrogen has '1' valence electron and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in NH_3 = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on N}=5-2-\frac{6}{2}=0

\text{Formal charge on }H_1=1-0-\frac{2}{2}=0

\text{Formal charge on }H_2=1-0-\frac{2}{2}=0

\text{Formal charge on }H_3=1-0-\frac{2}{2}=0

Hence, the Lewis-dot structure of NH_3 is shown below.

3 0
3 years ago
Help mee please (I will give the person who answers this a brainlist)
Leokris [45]
2 5 3 4 1 is the answers
7 0
3 years ago
Read 2 more answers
2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)
balandron [24]

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

3 0
2 years ago
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