<u>Question 1</u>
The formula mass of methanol is
g/mol.
Therefore, in 5.0 grams of methanol, there are
moles.
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<u>Question 2</u>
The formula mass of copper(II) carbonate is
g/mol.
This means that in 9.0 grams of copper(II) carbonate, there are
moles.
Using Avogradro's number, there are
molecules.
<u>Question 3</u>
The formula mass of cyclohexane is
g/mol.
So, 3.0 grams of cyclohexane is the same as
moles.
<u>Question 4</u>
The formula mass of benzene is
g/mol.
This means that 4.00 moles of benzene has a mass of
grams.
<u>Question 5</u>
1000 atoms of calcium is the same as
moles.
This is equal to
grams.
Answer:
I think <em><u>bar graph</u></em> is the appropriate way to present the data.
HNO₃ + H₂S → S + NO + H₂<span>O
Assign Oxidation Number:
L.H.S R.H.S
N in HNO</span>₃ = +5 +2 = N in NO
S in H₂S = -2 0 = S in S
Write Half cell Reactions:
Reduction Reaction:
3e⁻ + HNO₃ → NO -------(1)
Oxidation Reaction:
H₂S → S + 2e⁻ -------(2)
Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons.
6e⁻ + 2 HNO₃ → 2 NO
3 H₂S → 3 S + 6e⁻
Cancel e⁻s,
______________________________
2 HNO₃ + 3 H₂S → 2 NO + 3 S + H₂O
Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.
2 HNO₃ + 3 H₂S → 2 NO + 3 S + 4H₂O
<span>https://www.onetonline.org/find/career?c=6</span>
Answer:
B?
Explanation:
In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.