Answer:

Explanation:
The reaction we need to calculate:

1) 

We need the ClO in the products side, so we use the inverse of this reaction:


2) 

Now we need to combine this two:


The enthalpy of reaction:


<h3><u>Answer;</u></h3>
3.4 kJ
<h3><u>Explanation</u>;</h3>
Taking the mass of water as 10.0 g
Moles of water = Mass /molar mass
Moles of water in 10.0 g;
= 10g H2O x 1mol/18g
=0.56mol
But, 1 mole of water = 6.01 kJ
Hence;
6.01kJ/1mol H2O= x kJ/.56mol,
x = <u>3.4kJ</u>
Answer:

Explanation:
At same temperature and same number of moles, Using Boyle's law
Given ,
V₁ = 10 mL
V₂ = 20 mL
P₁ = 5.85 kPa
P₂ = ?
Using above equation as:

D.) He arranged elements by Atomic Masses