Question

A coaxial cable consists of an inner conductor with radius ri = 0.20 cm and an outer radius of ro = 0.4 cm and has a length of 13 meters. Plastic, with a resistivity of ρ = 2.00 ✕ 1013 Ω · m, separates the two conductors. What is the resistance (in Ω) of the plastic when current is flowing between the two conductors of the coaxial cable?

Answer 1

Answer:

$R = 1.69*10^{11} ohm$

Explanation:

ri = 0.20cm

ro = 0.4 cm

length L = 13m

resistivity \rho = 2.00*10^13 ohm m

resistance can be determine by using following relation

$R = \frac{\rho}{2\pi L} ln\frac{ro}{ri}$

$R = \frac{2.00*10^{13}}{2\pi *10} ln\frac{.004}{.002}$

$R = 1.69*10^{11} ohm$