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STatiana [176]
3 years ago
14

A coaxial cable consists of an inner conductor with radius ri = 0.20 cm and an outer radius of ro = 0.4 cm and has a length of 1

3 meters. Plastic, with a resistivity of ρ = 2.00 ✕ 1013 Ω · m, separates the two conductors. What is the resistance (in Ω) of the plastic when current is flowing between the two conductors of the coaxial cable?
Physics
1 answer:
N76 [4]3 years ago
4 0

Answer:

R = 1.69*10^{11} ohm

Explanation:

ri = 0.20cm

ro = 0.4 cm

length L = 13m

resistivity \rho = 2.00*10^13 ohm m

resistance can be determine by using following relation

R = \frac{\rho}{2\pi L} ln\frac{ro}{ri}

R = \frac{2.00*10^{13}}{2\pi *10} ln\frac{.004}{.002}

R = 1.69*10^{11} ohm

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Alex swims at an average speed of 45m/min. how far does he swim in 1 min 24 sec?
saveliy_v [14]

Answer:

63 m

Explanation:

Average speed of swimming = 45 m/min

Time = 1 minute 24 seconds

Converting time into minutes:

Formula:

Putting values, we get.

Thus, Alex swims for 63 m in 1 minute and 24 seconds.

6 0
3 years ago
Which explanation of the solar system best fits the observations of the planets and how they orbit the sun?
NeTakaya
You're right, Answer C

The dust and gas accumulate to form a solar nebula, which later on creates the star and the planets.
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3 years ago
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If the vertical axis and time on the horizontal axis if the speed is steadily increasing could the speef line ever become perfec
Phantasy [73]

A graph of real speed can have a section that's as steep as you want,
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Any vertical line on a graph, even it it's only a tiny tiny section, means
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8 0
3 years ago
Will give you brainliest pls help
ExtremeBDS [4]

1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].

2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].

3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].

4. Trick question? If the circuit becomes open, then no current will flow. Moreover, even if the voltmeter were kept as element of the circuit, voltmeters generally have a very high resistance (an ideal voltmeter has infinite resistance), so the current moving through the circuit will be negligible if not nil. In any case, the ammeter reading would be 0 A [choice B].

4 0
2 years ago
A 20-turn coil of area 0.32 m2 is placed in a uniform magnetic field of 0.055 T so that the perpendicular to the plane of the co
makvit [3.9K]

Answer:

1.5 * 10^-2 Tm^2

Explanation:

Electric Flux = B.A cos(theta)

B = 0.055 T

A = 0.32 m^2

theta = 30

Electric Flux = (0.055 T).(0.32 m^2).Cos(30) = 0.0152 = 1.5 * 10^-2 Tm^2

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