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AnnZ [28]
3 years ago
10

what is required to bring about a phase change 1.an increase or decrease in pressure 2.an increase or decrease in energy 3.an in

crease in energy only 3.a decrease in energy only
Physics
2 answers:
frozen [14]3 years ago
8 0

Answer

Correct answers are 1.an increase or decrease in pressure 2.an increase or decrease in energy

Explanation

All existing matter can undergo phase change it means they may transform from one state to another. phase change of a matter  may occur due to change in energy and change in pressures.

for example there is an ice cube which is a solid and if  we want to change it phase into liquid water for that purpose we have to supply some energy to ice cube it means we have to give some heat to ice cube. After supplying heat energy to the ice it will turn into water it means there is phase change from solid to liquid due to supplying the heat. Similarly we can change the liquid water into solid ice cube by taking heat energy(reducing temperature) from the liquid water  .

In some cases the matter doesn't want to undergo phase transformation. For example, oxygen will solidify at -361.8 degrees Fahrenheit at standard pressure.But , it can change to solid state at warmer temperatures when the pressure is increased.


sesenic [268]3 years ago
3 0

if you are wondering which one to put down on your test because it only allows you to chose on they want you to put down <em>an increase or decrease in energy </em>

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4 0
3 years ago
A statue falls into a pond a gardener states that the volume of the statue can be estimated by measuring the new water level exp
juin [17]
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5 0
3 years ago
A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change
Daniel [21]

Answer:

389 kg

Explanation:

The computation of mass is shown below:-

T = 2\pi \sqrt{\frac{m}{k} }

Where K indicates spring constant

m indicates mass

For the new time period

T^' = 2\pi \sqrt{\frac{m'}{k} }

Now, we will take 2 ratios of the time period

\frac{T}{T'} = \sqrt{\frac{m}{m'} }

\frac{1.50}{2.00} = \sqrt{\frac{0.500}{m'} }

0.5625 = \sqrt{\frac{0.500}{m'} }

m' = \frac{0.500}{0.5625}

= 0.889 kg

Since mass to be sum that is

= 0.889 - 0.500

0.389 kg

or

= 389 kg

Therefore for computing the mass we simply applied the above formula.

7 0
3 years ago
Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.
Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

A = (-D);A//D;

2A=-2D

B is parallel to C and in same direction.

B//C\\B=C\\

0.5B=0.5C\\

R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;

7 0
3 years ago
I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block
borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

T = 2\pi \sqrt{\frac{m}{k} }

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\

Now, determine the amplitude of oscillation, A;

E = \frac{1}{2} kA^2

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A =  \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm

Therefore, the amplitude of the oscillation is 2.82 cm

8 0
3 years ago
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