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Anna71 [15]
3 years ago
10

Taylor took 6 hours to drive home from college for Thanksgiving break, a total distance of 290 miles. She was able to average 50

miles per hour for part of the trip but had to slow down to 45 miles per hour for the rest of the time due to poor weather. How many hours did she drive each speed.
PLEASE SHOW WORK/HOW TO SOLVE IT :) ​
Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

  • 50 mph: 4 h
  • 45 mph: 2 h

Step-by-step explanation:

Let t represent the time driving at 50 mi/h. Then her total distance driven (in miles) is ...

  distance = speed · time

  290 = 50t + 45(6-t)

  20 = 5t . . . . . . . . . . . subtract 270, collect terms

  4 = t . . . . . . divide by the coefficient of t

Taylor drove 4 hours at 50 miles per hour, then 2 hours at 45 miles per hour.

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1 yard = 3 feet - so she can cut 3 x 3 = 9 out of each yard

18 x 9 = 162 pieces
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3 years ago
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The base of a solid is the region enclosed by the graphs of y=e^x, y=0, x=0, and x = 1. If each cross-section perpendicular to t
yanalaym [24]

Answer:

A

Step-by-step explanation:

The base of a solid in the region enclosed by the graphs of <em>y</em> = eˣ, <em>y</em> = 0, <em>x </em>= 0, and <em>x</em> = 1. Each cross-section perpendicular to the <em>x</em>-axis is an equilateral triangle. We want to find the volume of the solid.

Please refer to the graph below. We are concerned with the red region.

In order to find the volume, we essentially sum up the area of the figure at each <em>x</em> value. So, we integrate from <em>x </em> = 0 to <em>x </em>= 1.

The area for an equilateral triangle is given by:

\displaystyle A=\frac{\sqrt{3}}{4}s^2

Where <em>s</em> is the side length of the triangle.

Since the triangle lies perpendicular on the region, the side length of the triangle at <em>x</em> is simply <em>y</em>, which is eˣ.

Therefore, our volume is:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(y)^2\, dx

Substitute:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(e^x)^2\, dx

Evaluate the integral. Simplify:

\displaystyle V=\frac{\sqrt3}{4}\int_0^1e^{2x}\, dx

Integrate using u-substitution:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2x}\Big|_0^1\right)

Evaluate:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2(1)}-e^{2(0)} \right)

Therefore, the volume of the solid is:

\displaystyle V=\frac{\sqrt3}{8}\left(e^2-1\right)

Our answer is A.

3 0
3 years ago
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Determine the value of c that satisfies the given relation. 3c/1=c/2
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Answer:

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7 0
3 years ago
Is this right if not what’s the correct answer
noname [10]

hey friend your answer is

I hope it will helpful for you

mark as brainest answer

thank you

8 0
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Help please with this question​
torisob [31]

Answer: 70ft

Step-by-step explanation:

ht= (-3)^2 + 15(3) + 16

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ht= 70

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