Answer:
1. 230 kg...
W = m * g
W= 230 kg * 9.81 m/s^2
<u>W= 2256,3 N</u>
m= 230kg , W = 2256,3 N , g= 9.81 m/s^2
2. 887 N
W= m * g
887 N = m * 9.81 m/s^2
<u>m= 90,42 kg</u>
m= 90,42 kg, W = 887 N , g= 9.81 m/s^2
3. 420 kg
W= m * a
w= 420 kg * 9.81 m/s^2
<u>w=</u><u> </u><u>4120,2 N</u>
m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2
4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.
w = m * g
55.5 N = 15 kg * g
<u>a= 3,7 m/s^2</u>
m = 15 kg , W= 55.5 N , g= 3,7 m/s^2
Answer:
The right solution is "0.50 m/s²". A further explanation is provided below.
Explanation:
The given values are:
Mass,
m = 50 kg
Speed,
v = 10 m/s
Rolling friction acting backward (south),
f = 10 N
Air resistance acting backward (south),
= 15 N
The total force acting will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
Now,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.
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Let's look at the density of water at 25 deg C and compare that to a higher temperature, 80 deg C. The density decreases from 0.9970 g/mL to 0.9718 as it is heated. This makes sense because, as heat is added to the liquid water, there is greater kinetic energy of the molecules and there are also more vibrations of the water molecules. Together these mean that each H2O unit in liquid water takes up more space as the temperature increases.
