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2 years ago

How do kinetic and potential energy transfer to one throughout a roller coaster ride?

Physics

1 answer:

mojhsa [17]2 years ago

6 0

Answer:

As the cars ascend the next hill, some kinetic energy is transformed back into potential energy. Then, when the cars descend this hill, potential energy is again changed to kinetic energy. This conversion between potential and kinetic energy continues throughout the ride.

Explanation:

hope it helps U

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The cylindrical head bolts on a car are to be tightened with a torque of 63.3 N · m. If a mechanic uses a wrench of length 18.2

Nataly_w [17]

Answer: The perpendicular force to be used to tighten the bolt is

F=347.8N

Explanation:

Mathematically the torque is expressed as

T=F*L

Where T= torque in Nm

F= force in N

And L = perpendicular distance

Now given

T=63.3Nm

L=18.2cm to meter 18.2/100

0.182m

F=?

Making F the subject of the formula in our equation

F=T/L

F=63.3/0.182

F=347.8N

What is torque?

Torque is the product of force and perpendicular distance of the line of action.

6 0

4 years ago

Which element of a valid contract is established by getting the signatures of all parties?

sweet [91]

The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

<h3>What is an element of a valid contract?</h3>

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

Offer
Acceptance
Consideration
Intention to create legal relation
Certainty and capacity.

So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement

Learn more about elements of a valid contract:

brainly.com/question/15101023

#SPJ1

8 0

2 years ago

A car and a heavy truck roll down a hill and reach the bottom at the same speed. Compared with the momentum of the truck, the mo

RoseWind [281]

Answer:

A. less

Explanation:

The momentum of an object is directly proportional to it mass and velocity. It is the product of mass and velocity of the object. Given as

$Momentum (p) = Mass (m) \times Velocity (v)$

So the momentum of car,

$p_{c} = m_{c}\times v_{c}$

Momentum of truck,

$p_{t} = m_{t}\times v_{t}$

We know that, mass of car is less than that of truck and velocity of the two are same. It is implied that, momentum of car will be less than that of truck.

3 0

4 years ago

A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr

kolbaska11 [484]

Answer:

$0.002 N/C$

Explanation:

Parameters given:

Charge of object, q = 5 mC = $5 * 10^{-3} C$

Acceleration of object, a = $0.005 m/s^2$

Mass of object, m = 2.0 g

The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).

We know that Electrostatic force, F, is given in terms of Electric field, E, as:

F = qE

This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).

The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:

F = ma

Equating the two forces of the object, we get:

-qE = ma

=> $E = \frac{-ma}{q}$

Solving for E, we have:

$E = \frac{-2 * 10^{-3} * 0.005}{5 * 10^{-3}} \\\\\\E = -0.002 N/C$

The magnitude will be:

$|E| = |-0.002| N/C = 0.002 N/C$

The electric field has a magnitude of 0.002 N/C.

4 0

4 years ago

A car is traveling north at 17.7m/s After 12 s its velocity is 14.1m/s in the same direction. Find the magnitude and direction o

Nat2105 [25]

The car is initially traveling north at 17.7 m/s, and after 12 s, its velocity is 14.1 m/s, still due north. This means that the direction of the car has not changed, so we can already say that the direction of the acceleration is north (if the magnitude of the acceleration is positive) or south (if the magnitude of the acceleration is negative).

To find the magnitude of the average acceleration, we must calculate the ratio between the change in velocity and the time taken:

$a=\frac{v_f -v_i}{t}=\frac{14.1 m/s-17.7 m/s}{12 s}=-0.3 m/s^2$

Since the acceleration is negative, it means it is in the opposite direction to the motion of the car, therefore south. Therefore, the correct answer is

b) 0.30 m/s2, south

7 0

3 years ago