Answer:
Explanation:
We are given that
Magnitude of vector v=
v lies in the first quadrant
Substitute the values then we get
Therefore, the vector v in component form
use the formula: v^2=(3kT)/m
Where:
<em>v is the velocity of a molecule</em>
<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>
<em>T is the temperature of the molecule in the air</em>
<em>m is the mass of the molecule</em>
For an H2 molecule at 20.0°C (293 K):
v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)
v^2 = 3.65e+6 m^2/s^2
v = 1.91e+3 m/s
For an O2 molecule at same temp.:
v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)
v^2 = 2.28e+5 m^2/s^2
v = 478 m/s
Therefore, the ratio of H2:O2 velocities is:
1.91e+3 / 478 = 4.00
Answer:
330 kg for high density liquid
255 kg for low density liquid
Explanation:
Density is defined as mass per unit volume hence expressed as p=m/v where p is density, m is mass and v is volume. Making m the subject of the formula then m=pv
The volume of the given container is given by lwh where l is length, w is width and h is height. Substituting 3m, 0.4 m and 0.5 m for l, w and h then volume is 3*0.4*0.5=0.6 cubic metres
Since the liquids are mixed equally, volume for each is 0.6/2=0.3 cubic metres
Mass of first liquid will be 1100*0.3=330 kgs
Mass for other liquid whose density is 850 kg/m3 will be 0.3*850= 255 Kgs
