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Oxana [17]
3 years ago
13

Smoke is an example of a? Substance Solution Colloid Suspension

Physics
2 answers:
Bess [88]3 years ago
5 0
The answer is Colloid
dusya [7]3 years ago
4 0

Colloid is your answer ma’am.

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If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.
Alexeev081 [22]

Answer:

v=

Explanation:

We are given that

Magnitude of vector v=\mid v\mid =4

v lies in the first quadrant

\theta=\frac{\pi}{3}

v_x=\mid v\mid cos\theta

v_y=\mid v\mid sin\theta

Substitute the values then we get

v_x=4cos\frac{\pi}{3}

v_x=4\times \frac{1}{2}=2

cos\frac{\pi}{3}=\frac{1}{2}

v_y=4\times sin\frac{\pi}{3}=4\times \frac{\sqrt 3}{2}=2\sqrt 3

sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Therefore, the vector v in component form=

v=

4 0
4 years ago
Which of the following statements is NOT correct?
Flauer [41]
The answer is
D:if the
6 0
3 years ago
The molecular weight of oxygen gas (o2) is 32 while that of hydrogen gas (h2) is 2.
anzhelika [568]

use the formula: v^2=(3kT)/m

Where:

<em>v is the velocity of a molecule</em>

<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>

<em>T is the temperature of the molecule in the air</em>

<em>m is the mass of the molecule</em>

For an H2 molecule at 20.0°C (293 K):

v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)

v^2 = 3.65e+6 m^2/s^2

v = 1.91e+3 m/s

For an O2 molecule at same temp.:

v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)

v^2 = 2.28e+5 m^2/s^2

v = 478 m/s

Therefore, the ratio of H2:O2 velocities is:

1.91e+3 / 478 = 4.00

7 0
3 years ago
A young owl forgets how to fly for a moment and is free falling towards the ground. Before crashing, he remembers how to fly and
Oksi-84 [34.3K]

did you figure it out

5 0
4 years ago
Read 2 more answers
7. Two liquid density 1100kg/m³ and 850kg/m³are mixed in equal volumes. The
ivolga24 [154]

Answer:

330 kg for high density liquid

255 kg for low density liquid

Explanation:

Density is defined as mass per unit volume hence expressed as p=m/v where p is density, m is mass and v is volume. Making m the subject of the formula then m=pv

The volume of the given container is given by lwh where l is length, w is width and h is height. Substituting 3m, 0.4 m and 0.5 m for l, w and h then volume is 3*0.4*0.5=0.6 cubic metres

Since the liquids are mixed equally, volume for each is 0.6/2=0.3 cubic metres

Mass of first liquid will be 1100*0.3=330 kgs

Mass for other liquid whose density is 850 kg/m3 will be 0.3*850= 255 Kgs

3 0
3 years ago
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