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torisob [31]
3 years ago
15

I don’t get science at all my teacher doesn’t explain anything and I was out of school can anyone explain this to me

Physics
1 answer:
bekas [8.4K]3 years ago
5 0
2. Groups
3.Ion
4.NonPolar
5.Metallic Bond
6.Make up most of the atom's mass
7.Atomic Number
8.Seven
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A type O star is likely to appear _____. yellow, blue, green or red
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A type O star is likely to appear blue. 
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The angle between the axes of two polarizing filters is 45.0^\circ45.0 ​∘ ​​ . By how much does the second filter reduce the int
suter [353]

Answer

given,                                                                      

angle between two polarizing filters = 45°

filter reduce intensity = ?                          

a) I = I₀ Cos² θ                                

here θ = 45⁰                                

I = \dfrac{I_0}{2}                      

intensity of the light is reduced by 0.500

correct answer from the given option D

b) direction of the polarization                    

                        θ = 45°                  

7 0
3 years ago
A floating ice block is pushed through a displacement d = (13.5 m)i + (-14.3 m)j along a straight embankment by rushing water, w
fredd [130]

To solve this problem, we are going to use the formula for work which is Fd where x and y are measured separately.

 

X direction: W = 13.5 x 230 = 3105 Joules

Y direction: W = -14.3 x -165 = 2360 Joules

So the total work is getting the sum of the two: 3105 + 2360 = 5465 Joules

7 0
3 years ago
the record for a ski jump is 180 m set in 1989. Assume the jumper comes off the end of the ski jump horizontally and falls 90 m
Mashutka [201]
Let's write the equations of motion on both x- (horizontal) and y- (vertical) axis. On the x-axis, it's a uniform motion with constant velocity vx. On the y-axis, it is a uniformly accelerated motion with initial height h=90 m and acceleration of g=9.81 m/s^2 pointing down (so with a negative sign):
S_x(t)=v_x t
S_y(t)=h- \frac{1}{2} gt^2

First, let's find the time at which the jumper reaches the ground. This happens when Sy(t)=0:
0=h- \frac{1}{2} g t^2
and so 
t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2\cdot 90m}{9.81 m/s^2} }=4.28 s

Then, we can find the horizontal speed. In fact, we know that at the time t=4.28 s, when the jumper reached the ground, he covered exactly 180 m, so Sx=180 m. Using this into the law of motion in x, we find
v_x= \frac{S_x}{t} = \frac{180 m}{4.28 s} =42 m/s

8 0
3 years ago
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