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kow [346]
3 years ago
7

A man is jogging at 3 m/s. If his mass is 85 kg, what is his kinetic energy?

Physics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

This is the complete answer and step by step explanation.

Given:

a = 3m/s

m = 85 kg

Unknown:

The Kinetic energy of the man jogging

Formula and solution:

KE = 1/2 mv²

KE = 1/2(85 kg)(3 m/s)²

KE =  (42.5 kg)(9 m²/s²)

Final Answer:

KE = 382.5 kg.m²/s² or simplify as 382.5 J is the kinetic energy of man jogging

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1 point
Tju [1.3M]

Answer:

Option A nuclear

Explanation:

The rate of electricity production in nuclear power plant is much higher as compared to the rate of electricity generation in gas, wind and solar power plants.

Thus, in case where large amount of electricity is to be produced in a short period then one must rely on nuclear power plants.

Therefore, option A is correct

7 0
3 years ago
What is the resolution of an analog-to-digital converter with a word length of 12 bits and an analogue signal input range of 100
Elena L [17]

Answer:

The resolution of an analog-to-digital converter is 24.41 mV

Explanation:

Resolution of an analog-to-digital  = (analogue signal input range)/2ⁿ

where;

n is the number or length of bit, and in this question it is given as 12

Also, the analogue signal input range is 100V

Resolution of an analog-to-digital  = 100V/2¹²

2¹² = 4096

Resolution of an analog-to-digital  = 100V/4096

Resolution of an analog-to-digital  = 0.02441 V = 24.41 mV

Therefore, the resolution of an analog-to-digital converter is 24.41 mV

5 0
4 years ago
While on vacation, Carine rides in a hot-air balloon. To make the balloon rise, the pilot turns on a flame to warm the air insid
andre [41]

The air inside becomes warmer, and that makes it LESS DENSE.

Less-dense air FLOATS in denser air. Since it's inside the balloon, it picks the balloon up when it floats.

3 0
3 years ago
A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i
tresset_1 [31]

Answer:

a) Acceleration of the car is given as

a_{car} = -21 m/s^2

b) Acceleration of the truck is given as

a_{truck} = 10.15 m/s^2

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

m_1v_1 + m_2v_2 = (m_1 + m_2)v

now we have

1400 (6.32) + 2900(0) = (1400 + 2900) v

v = 2.06 m/s

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

a_{car} = \frac{v_f - v_i}{t}

a_{car} = \frac{2.06 - 6.32}{0.203}

a_{car} = -21 m/s^2

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

a_{truck} = \frac{v_f - v_i}{t}

a_{truck} = \frac{2.06 - 0}{0.203}

a_{truck} = 10.15 m/s^2

5 0
3 years ago
In this ecosystem, squirrels find and eat acorns from trees. What would happen to the balance of the ecosystem if populations of
Marizza181 [45]

<em><u>Answer</u></em>

The answer would be B.

7 0
4 years ago
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