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3 years ago

2 Points

Mathematics

1 answer:

gtnhenbr [62]3 years ago

5 0

B. (x-5) is a factor.

<u>Step-by-step explanation:</u>

To find out the relationship among the factor and an expression, we have to factorise it as,

2x² - 7x - 15

Here, sum = coeff. of x = -7

Product = constant × coeff of x² = -15 × 2 = -30

Now we have to find 2 numbers, which satisfies the above 2 conditions are -10 and 3.

-10 +3 = -7

-10× 3 = -30

2x² - 7x - 15

= 2x²- 10x + 3x - 15

Taking common terms as,

= 2x(x-5) +3(x - 5)

= (2x+3) (x-5)

So the expression is factorized and (x-5) is one of the factors of the expression.

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A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m

Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

z statistic is computed as follows:

z= $\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } }$ where

X is the proportion of correct answers in the test ( $\frac{30}{40}$ )
M is the expected proportion of correct answers according to the null hypothesis (0.5)

p is the probability of correct answer (0.5)
N is the total number of questions in the test (40)

z= $\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } }$ ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

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3 years ago

Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded

slega [8]

Answer:

$4.5 cm=L2$

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

$H=\sqrt{L1^{2}+L2^{2} }$

Where:

$H=6 cm$

$L1=4 cm$

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We isolate our incognita an we get:

$\sqrt{H^{2}-L1^{2}} =L2$

We supplant with the given data:

$\sqrt{(6cm)^{2}-(4cm)^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{20cm^{2}} =L2$

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3 years ago

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3 years ago

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e-lub [12.9K]

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