Answer:
Initial state Final state
3 ⇒ 2
3 ⇒ 1
2 ⇒ 1
Explanation:
For this exercise we must use Bohr's atomic model
E = - 13.606 / n²
where is the value of 13.606 eV is the energy of the ground state and n is the integer.
The energy acquired by the electron in units of electron volt (eV)
E = e V
E = 12.5 eV
all this energy is used to transfer an electron from the ground state to an excited state
ΔE = 13.6060 (1 / n₀² - 1 / n²)
the ground state has n₀ = 1
ΔE = 13.606 (1 - 1/n²)
1 /n² = 1 - ΔE/13,606
1 / n² = 1 - 12.5 / 13.606
1 / n² = 0.08129
n = √(1 / 0.08129)
n = 3.5
since n is an integer, maximun is
n = 3
because it cannot give more energy than the electron has
From this level there can be transition to reach the base state.
Initial state Final state
3 ⇒ 2
3 ⇒ 1
2 ⇒ 1
Answer:
A horse pulls a wagon along a road
Answer:
C. Momentum is conserved but not kinetic energy.
Explanation:
This case represents an entirely inelastic collision, that is, a collision between the car and the truck that reduces total kinetic energy of the entire system, whereas linear momentum is conserved. Hence, correct answer is C.
Answer:
The volume at the surface is 10.97 L.
Explanation:
Given that,
Volume = 5.5 L
Height = 10 m
Density of sea water= 1025 kg/m³
We need to calculate the pressure at that point
Using formula of pressure
![P'=P+\rho gh](https://tex.z-dn.net/?f=P%27%3DP%2B%5Crho%20gh)
Put the value into the formula
![P'=1.01\times10^{5}+1025\times9.8\times10](https://tex.z-dn.net/?f=P%27%3D1.01%5Ctimes10%5E%7B5%7D%2B1025%5Ctimes9.8%5Ctimes10)
![P'=201450\ Pa](https://tex.z-dn.net/?f=P%27%3D201450%5C%20Pa)
We need to calculate the volume at the surface
Using equation of ideal gas
![PV= RT](https://tex.z-dn.net/?f=PV%3D%20RT)
So, for both condition
![PV=P'V'](https://tex.z-dn.net/?f=PV%3DP%27V%27)
Put the value into the formula
![V=\dfrac{201450\times5.5}{1.01\times10^{5}}](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B201450%5Ctimes5.5%7D%7B1.01%5Ctimes10%5E%7B5%7D%7D)
![V=10.97\ L](https://tex.z-dn.net/?f=V%3D10.97%5C%20L)
Hence, The volume at the surface is 10.97 L.
Emf = d (phi-B) / dt
<span>B dA/dt, where dA/dt is the area swept out by the wire per unit time. </span>
<span>0.88 V = (0.075 N/(A m)) (L)(4.20 m/s), so </span>
<span>L = (0.88 J/C) / [ (0.075 N s/C m)(4.2 m/s) ] = about 3 meters</span>