Answer:
The speed and direction of the two players immediately after the tackle are 3.3 m/s and 53.4° South of West
Explanation:
given information:
mass of fullback,
= 92 kg
speed of full back,
= 5.8 to south
mass of lineman,
=110 kg
speed of lineman,
= 3.6
according to conservation energy,
assume that the collision is perfectly inelastic, thus
initial momentum = final momentum
=
'
m₁v₁ = (m₁+m₂)
'
' = m₁v₁/(m₁+m₂)
= (92) (5.8)/(92+110)
= 2.64 m/s
=
'
m₂v₂ = (m₁+m₂)
'
' = m₁v₁/(m₁+m₂)
= (110) (3.6)/(92+110)
= 1.96 m/s
thus,
' = √
'²+
'²
= 3.3 m/s
then, the direction of the two players is
θ = 90 - tan⁻¹(
'/
')
= 90 - tan⁻¹(1.96/2.64)
= 53.4° South of West
Answer:
P = 0.0644 atm
Explanation:
Given that,
The pressure of a sample of gas is measured as 49 torr.
We need to convert this temperature to atmosphere.
The relation between torr and atmosphere is as follow :
1 atm = 760 torr
1 torr = (1/760) atm
49 torr = (49/760) atm
= 0.0644 atm
Hence, the presssure of the sample of gas is equal to 0.0644 atm.