Answer:
Static electricity : is a familiar electric phenomenon in which charged particles are transferred from one body to another
Ohm's law : states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance
Answer:
The magnitude of the tension in he string is equal to the magnitude of the weight of the object.
Explanation:
According to the Newton's 1st law, An object will remain at rest or in uniform motion in a straight line unless acted upon by an unbalanced force.
In here, the elevator is moving with a constant speed. So the object must have the equal constant speed. Which means, it has a uniform motion. According to Newton's 1st law, the total unbalanced force on the object must be zero . As we know, there are only two forces are on the object and they are,
The tension in string(T) , The weight of the object(W) .
∴ F = 0
T - W = 0
So to balanced those forces, the magnitude of the tension in the string must be equal to the magnitude of the weight of the object.
Time = 15/-0.5 = 14.5/-0.5 = 14.5s
The answer is 14.5s
Sorry no one would answer it sooner.
Answer:
The escape speed for the craft is 1.49 m/s.
Explanation:
In this case we need to find the escape speed for a craft launched from a space elevator at a height of 56,000 km. The escape velocity is given by :

Here,
G is universal gravitational constant
M is mass of earth
d = r + h, r is radius of Earth

So, the escape speed for the craft is 1.49 m/s.