Ask question

Ask question

All categories

2 years ago

8

What is the direction of the force of an object moving in a circle?

1 answer:

Ivanshal [37]2 years ago

7 0

Answer:

The answer is 45 degree angle

You might be interested in

Wts the average velocity

Alexeev081 [22]

Answer:

2.11 m/s

Explanation:

V=disp/time

V=(0.52m+3.7m)/(2)

V=4.22/2

V=2.11 m/s

5 0

3 years ago

Predict what the MASS would be of something exerting a force of 45N on a spring scale. EXPLAIN how you got

a_sh-v [17]

The mutual forces of gravity between the Earth and an object on or near
its surface are (<em>mass of the object</em>) x (<em>acceleration of gravity on Earth</em>).
These two forces are equal, and we call their strength the "weight" of
the object. It's the number shown on the scale as long as nobody has
their thumb on the scale. In this problem, the force is 45N . (That's
about 10.12 pounds.)

The acceleration of gravity on Earth is about 9.8 meters per second² .

So 45N = (mass in kilograms) x (9.8 meters per second²)

Divide each side by 9.8 : Mass = 45/9.8 = <u>4.59 kilograms</u> (rounded)

8 0

3 years ago

A car with a mass of 1,400 kg is traveling at a speed of 40 m/s. What is its momentum?

adell [148]

Answer:

The answer is

<h2>56,000 kgm/s</h2>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

m = 1400 kg

v = 40 m/s

We have

momentum = 1400 × 40

We have the final answer as

<h3>56,000 kgm/s</h3>

Hope this helps you

7 0

3 years ago

A car is designed to get its energy from a rotating

nydimaria [60]

Answer:

(a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power $P= 15.0 hp = 15.0\times746=11190 watt$

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{2}mr^2$

Put the value into the formula

$I=\dfrac{1}{2}\times475\times(1.50)^2$

$I=534.375\ kg m^2$

(a). We need to calculate the kinetic energy stored in the fly wheel

Using formula of K.E

$K.E=\dfrac{1}{2}I\omega^2$

Put the value into the formula

$K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2$

$K.E=46880620.9\ J$

$K.E =46.88\times10^{6}\ J$

$K.E =46.88\ MJ$

(b). We need to calculate the length of time the car could run before the flywheel would have to be brought backup to speed

Using formula of time

$t=\dfrac{46.88\times10^{6}}{11190}$

$t=4189.45\ sec$

$t=1.163\ hours$

Hence, (a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

3 0

3 years ago

What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9

mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

$v_f^2 = v_i^2 + 2 a \Delta y$

where

$v_f$ is the final velocity

$v_i$ is the initial velocity

a is the acceleration

$\Delta y$ is the distance covered

For the particle in free-fall in this problem, we have

$v_i = 0$ (it starts from rest)

$v_f = 7.9 m/s$

$g=9.8 m/s^2$ (acceleration due to gravity)

By re-arranging the equation, we can find the distance travelled:

$\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m$

5 0

3 years ago