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Sergio [31]
3 years ago
6

Compare 7/8 with 14/16 using ( <,>,= )

Mathematics
2 answers:
Anna35 [415]3 years ago
8 0
Answer is C they are equal.
Goryan [66]3 years ago
5 0
I just took the test and the answer is <span>C 7/8 = 14/16</span>
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What the circumference of a circle with a diameter of 25 inches use 3.14 for pi?
Snowcat [4.5K]

Answer:

78.5 inches

Step-by-step explanation:

The formula for the circumference of a circle is \pi d.

So the circumference of this circle is 3.14*25=78.5 (in)

4 0
2 years ago
|x-3|+5 <br> i need to find out the absolute value
Assoli18 [71]
I got 5 I’m not for sure tho
7 0
3 years ago
Read 2 more answers
A number cube was rolled as part of an experiment. The results are in the table below. The fraction StartFraction 1 over x EndFr
Svetlanka [38]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
what are two practical products you could add to find 990 x 37 ; 297 693 2970 6930 69300 6330 29700
VMariaS [17]
First evaluate 990 x 37.
990 x 37 = 36630

Test the given numbers to find the pair that adds up to 36630.
Test 297.
The missing pair will be
36630 - 297 = 36333
Will not work

Test 693.
36630 - 693 = 35937
Will not work

Test 2970.
36630 - 2970 = 33660
Will not work

Test 6930
36630 - 6930 = 29700
This works, because 6930 + 29700 = 36630.

Answer: 6930 and 29700.


8 0
3 years ago
Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x
charle [14.2K]

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

             a = 5

             b = x - 1

             c = x

Step:1

      Pythagorean theorem is,

              a^{2} + b^{2} = c^{2}................................(1)

      (  It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

      From the given values the equation (1) becomes,

                       5^{2} + (x-1) ^{2} = x^{2}

                             ( (a-b)^{2} = a^{2}  + b^{2} -2ab )

               25 + ( x^{2} + 1 - 2x ) = x^{2}

                           25 + 1 -2x = 0               ( ∵ Eliminate x^{2} in both sides)

                                     26 = 2x

                                       x = 13

Step:2

        From the values of x,

                   a = 5

                    b = ( 13 - 1 ) = 12

                   c = 13

Result:

            The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

3 0
3 years ago
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