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Xelga [282]
4 years ago
14

Corresponding propositions cannot both be false.

Physics
2 answers:
Fofino [41]4 years ago
8 0

Answer:

Suggestions are opposite when the two of them can't be valid. An A suggestion, e.g., "all giraffes have long necks" can't be valid simultaneously as the comparing E recommendation: "no giraffes have long necks." Note, in any case, that relating An and E suggestions, while opposite, are not conflicting.

Explanation:

mart [117]4 years ago
4 0
Wait so they can’t?!
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All of the following are benefits of statistics except that it __________. A. increases knowledge B. promotes change C. creates
erastovalidia [21]
C. creates biases
this is the only answer that would be a disadvantage. 
5 0
3 years ago
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a test tube has a diameter of 3cm . how many turns would a piece of thread of length 90.42 make round test tube​
nadya68 [22]

Answer:

4.8 turns would be made around the tube

Explanation:

You need the circumference of the tube since it's just a lifted circle

2×pi×3=18.85

90.42/18.85=4.79

And round that to 4.8

6 0
3 years ago
)consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particl
I am Lyosha [343]

here force between two particles is given by Coulomb's law where two particles will either repel or attract each other

this force of attraction or repulsion is given by the equation

F = \frac{kq_1 q_2}{r^2}

here we know that

q_1 , q_2 = two point charges

r = distance between two charges

so now we will substitute all values in it

F = \frac{kq_0q_1}{d_1^2}

so above is the force between two point charges

5 0
3 years ago
Which of these would be caused by a chemical change?
olganol [36]

Answer:

which of what?

Explanation:

7 0
4 years ago
A light with frequency of 3.5 x 10^15 Hz is utilized to illuminate the selenium metal (work function 5.11 eV). What will be the
ruslelena [56]

Answer:

The maximum speed of the ejected photoelectrons is 1.815 x 10⁶ m/s.

Explanation:

Given;

frequency of the light, f = 3.5 x 10¹⁵ Hz

work function of the metal, Φ = 5.11 eV

                                              Φ = 5.11 x 1.602 x 10⁻¹⁹ J = 8.186 x 10⁻¹⁹ J

The energy of the incident light is given as sum of maximum kinetic energy and work function of the metal.

E = K.E + Φ

where;

E is the energy of the incident light, calculated as;

E = hf

E = (6.626 x 10⁻³⁴)(3.5 x 10¹⁵)

E = 2.319 x 10⁻¹⁸ J

The maximum kinetic energy of the photoelectrons is calculated as;

K.E = E - Φ

K.E = 2.319 x 10⁻¹⁸ J  - 8.186 x 10⁻¹⁹ J

K.E =  2.319 x 10⁻¹⁸ J - 0.8186 x 10⁻¹⁸ J

K.E = 1.5004 x 10⁻¹⁸J

The maximum speed of the ejected photoelectrons in 10⁶ m/s  is given as;

K.E = ¹/₂mv²

v_{max}^2 = \frac{2K.E}{m} \\\\v_{max}= \sqrt{\frac{2K.E}{m}} \\\\v_{max} =  \sqrt{\frac{2(1.5 \ \times \ 10^{-18})}{(9.11 \ \times \ 10^{-31})}}\\\\v_{max} =1.815 \ \times \ 10^{6} \ m/s

Therefore, the maximum speed of the ejected photon-electrons is 1.815 x 10⁶ m/s.

4 0
3 years ago
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