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pishuonlain [190]
3 years ago
14

Define work and power

Physics
1 answer:
Kamila [148]3 years ago
7 0
WORK = W=Fd. Because energy is the capacity to do work , we measure energy and work in the same units (N*m or joules). POWER (P) is the rate of energy generation (or absorption) over time:P = E/t. Power's SI unit of measurement is the Watt, representing the generation or absorption of energy at the rate of 1 Joule/sec.
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I would think the answer is c.

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The components of a 15 meters per second velocity at an angle of 60 degrees above the horizontal are?
mafiozo [28]

Answer:

x-component of velocity: 7.5 m/s

y-component of velocity: 13 m/s

Explanation:

This problem is pure trigonometry. Assuming you know trig, there are only a couple of steps to solving this problem. First, split the velocity into components; recall that any vector not directed along an axis has x and y components. Then, remember that sinΘ = opposite/hypotenuse. Applying this to your scenario, you get sin60° = vy/15. Multiplying this out gives you vy=15sin60. Put this into a calculator (make sure it's set to degree mode because the angle in this problem is in degrees) and you should get 12.99, which you can round up to 13 m/s. This is the velocity in the y-direction.

The procedure to find the x-velocity is very similar, but instead of using sine, we will use the cosine of theta. Recall that cosΘ=adjacent/hypotenuse. Once again plugging this scenario's numbers into that, you end up with cos60 = vₓ/15. Multiplying this out gives you vₓ = 15cos60. Once again, plug this into your calculator. 7.5 m/s should be your answer. This is the velocity in the x-direction.

By the way, a quick way to find the components of a vector, whether it's velocity, force, or whatever else, is to use these functions. Generally, if the vector points somewhere that's not along an axis, you can use this rule. The x-component of the vector is equal to hypotenuse*cosΘ and the y-component of the vector is equal to hypotenuse*sinΘ.

8 0
2 years ago
Which liquid is more dense ???? alcohol or water
Nady [450]
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lora16 [44]

Answer:

\theta=145

Explanation:

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B=2Acos(\theta/2)\\

A, is the amplitude from the identical harmonic waves

B, is the amplitude of the resultant wave

θ, is the phase, between the waves

The amplitude of the combined wave must be 0.6A:

0.6A=2Acos(\theta/2)\\ cos(\theta/2)=0.3\\\theta/2=72.5\\\theta=145

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