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KiRa [710]
3 years ago
13

Does the atmosphere contain 21% nitrogen in 78% oxygen

Physics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases

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Static discharge differs from electric current because static discharge is described by which of the following?
Bond [772]
<span>Static discharge differs from electric current because static discharge is described by C. lasting for only a fraction of a second.
This is a very short period of time, and electric current lasts longer than a static discharge does. 
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4 years ago
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A ramp is 2.8 m long and 1.2 m high. How much power is needed to push a box up the ramp in 4.6 s with a force of 96 N?
tino4ka555 [31]
Power = work /time

and  W = force * dis

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4 years ago
What are three areas of science that rely on physical science?
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A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t
Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

y=\frac{1}{2}at^2

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s

10.87 seconds

F) The velocity just before the rocket arrives to the ground is:

v=\sqrt{2gy}=\sqrt{2(9.8m/s ^2)(580m)}=106.62\frac{m}{s}

6 0
3 years ago
What is the weight, in pounds, of a 205-kg object on jupiter?
Crazy boy [7]
<span>a 205 kg mass object will weight 1143.43 lbs on Jupiter. Looking up the surface gravity of Jupiter, you can find that it's 2.53 times that of earth. So the 205 kg object will weigh 205 * 2.53 = 518.65 kg on Jupiter. Now we need to convert from kg to pounds. This is done by multiplying by 2.20462 518.65 kg * 2.20462 lb/kg = 1143.43 lb</span>
4 0
3 years ago
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