The charge would be in equilibrium so there would be no charge in the body of the conductor.
Answer:
(b) there cannot be any charge in the body of the conductor
Answer:
D
Explanation:
The forces have the same magnitude (3N), but different directions. So they are different.
Answer:
The correct answer is b, x = 9 cos (pi / 2 t)
Explanation:
The equation that describes a simple pendulum is
θ = θ₀ cos (wt + φ)
The angle is measured is radians
θ = x / L
We replace
d / L = x₀ / L cos (wt + φ)
x₀ = 9 in
We replace
d = 9 cos (wt + φ)
Angular velocity is related to frequency and period.
w = 2π f = 2π / T
The period is the time of a complete oscillation T = 4 s
w =2π / 4
w = π / 2
Let's replace
x = 9 cos (π/2 t + φ)
As the system is released from the root x = x₀ for t = 0 s
x₀ = x₀ cos φ
Cos φ = 1
φ = 0°
The final equation is
x = 9 cos (pi / 2 t)
The correct answer is b
Answer:
a) 0.0875A
b) 2.06*10^-6m/s
Explanation:
given
Diameter, d = 2.6mm = 0.0026m
Charge, Q = 420C
Time, t = 80mins = 80*60s = 4800s
Concentration of electrons, n = 5*10^28
To find the current, recall that q = it
Therefore, i = Q/t
Current, i = 420/4800
i = 0.0875A
To get the drift velocity, recall that I = n*q*Vd*A
A = πd²/4
A = π*0.0026²/4
A = 5.3*10^-6m²
Then, Vd = I/nqA
Vd = 0.0875/(5*10^28 * 1.6*10^-19 * 5.3*10^-6)
Vd = 0.0875/42400
Vd = 2.06*10^-6m/s
Note, low Vd causes low current.
Therefore, the current is 0.0875A and the Vd is 2.06*10^-6m/s
