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lord [1]
3 years ago
8

A 50Kg girl jumps off a 5-meter-high diving board. What is her kinetic energy right before she hits the water?

Physics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

2450 J

Explanation:

Given that,

A 50Kg girl jumps off a 5-meter-high diving board.

We need to find the kinetic energy of the girl before she hits the water. At this point the kinetic energy becomes equal to the potential energy such that,

K=mgh\\\\K=50\times 9.8\times 5\\\\K=2450\ J

So, her kinetic energy right before she hits the water is equal to 2450 J.

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Answer:

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Total force = mass * acceleration + frictional force

260 = 40 a + 80

a = 180 / 40 = 4.5 m/s^2

Check:

15 a + 15 * 10 * .2 = T    acceleration of 15 kg block (assuming a = 4.5)

T = 15 (4.5) + 30 = 97.5     force required to accelerate 15 kg block

260 - 97.5 = 162.5     net force on 25 kg block

162.5 = 4.5 (25) + 25 * 10 * .2

162.5 = 112.5 + 50 = 162.5

4.5 m/s^2 checks out as correct

8 0
2 years ago
Hehe i hate being a single girl....what physical properties dose europium have
sasho [114]

Answer:

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Explanation:

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3 0
3 years ago
three carts of masses 2 kg, 18 kg, and 9 kg move on a frictionless horizontal track with speeds of 10m/s, 8m/s, and 2m/s. the ca
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Answer:

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Explanation:

Given:

m₁ = 2 kg

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m₃ = 9 kg

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__________

V - ?

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m₁·V₁ + m₂·V₂ + m₃·V₃ = (m₁ +m₂ + m₃) ·V

Cart speed after interaction:

V = ( m₁·V₁ + m₂·V₂ + m₃·V₃ ) / (m₁ +m₂ + m₃)

V = (2·10 + 18·8 + 9·2) / ( 2 + 18 + 9) = 182 / 29 ≈  6.3 m/s

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Answer:

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