Seven valence electrons is your answer
Answer:
Mass = 38.3 g
Explanation:
Given data:
Mass of Cl₂ required = ?
Mass of phosphorus = 10.6 g
Solution:
Chemical equation:
P₄ + 6Cl₂ → 4PCl₃
Number of moles of P₄:
Number of moles = mass/ molar mass
Number of moles = 10.6 g/123.9 g/mol
Number of moles = 0.09 mol
Now we will compare the moles of P₄ with Cl₂ from balance chemical equation.
P₄ : Cl₂
1 : 6
0.09 : 6×0.09 = 0.54 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.54 mol × 70.9 g/mol
Mass = 38.3 g
<h3>
Answer:</h3>
0.00245 moles of HCl
<h3>
Explanation:</h3>
We are given;
Volume of KOH = 9.71 mL
Molarity of KOH = 0.252 M
Volume of HCl = 15.0 mL
We are required to determine the number of moles of HCl
<h3>Step 1: Write the balanced equation for the reaction</h3>
The reaction between HCl and KOH is given by;
KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)
<h3>Step 2: Calculating the number of moles of KOH</h3>
Molarity = Moles ÷ Volume
Rearranging the formula;
Moles = Molarity × Volume
= 0.252 M × 0.00971 L
= 0.00245 moles
<h3>Step 3: Moles of HCl </h3>
From the equation, 1 mole of KOH reacts with 1 mole of HCl
Therefore, the mole ratio of KOH : HCl is 1 : 1
Thus,
Moles of HCl will be 0.00245 moles
Therefore, there are 0.00245 moles of HCl in the solution.
