A food web is graphical representation of what eats what in an ecological community and is formed by the natural interconnection of food chains.
Freshwater mussel are important components of food webs. They are omnivores and they feed upon algae, zooplanktons, bacteria and dissolved organic matter.
- If a virus wiped out the mussel population, the consumer (seagull, octopus, human) may not starve or die as they have other sources of food available. The other food sources available for human is fish, shark and octopus, for seagull is fish and for octopus is limpets. However as the consumer have lost a source of food, the competition for other food sources will increase. Competition occurs in a food web as individuals of different species struggle to obtain the same food.
- The two other consumer of mussels are-human and octopus.
- The population of consumers may not change drastically as other food sources are available.
Learn more about food web-
brainly.com/question/18816028
Answer:
66.4 mL
Explanation:
A 75.7% (v/v) value, means that f<u>or every 100 mL of rubbing alcohol, there are 75.7 mL of isopropanol.</u>
With the above information in mind, we can s<u>olve the problem by multiplying 87.7 mL by 75.7 %</u>:
87.7 mL * 75.7 / 100 = 66.4 mL
So there are 66.4 mL of isopropanol in 88.7 mL of rubbing alcohol.
The balanced equation for the above reaction is
2Al + 6H₂O ---> 2Al(OH)₃ + 3H₂
stoichiometry of Al to H₂ is 2:3
number of Al moles reacted - 78.33 g / 27 g/mol = 2.901 mol
according to molar ratio
2 mol of Al forms - 3 mol of H₂
therefore 2.901 mol of Al - forms 3/2 x 2.901 = 4.352 mol
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP
if 1 mol occupies 22.4 L
then 4.352 mol occupies - 22.4 L/mol x 4.352 mol = 97.48 L
volume occupied by H₂ is 97.48 L
Answer:
The balance of chemical equation is given below.
3Ca + N2------ Ca3N2