Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
M₁V₁ = M₂V₂
0.0952 M * 38.73 mL = M₂* 49.48 mL
M₂ = 0.0745 M
Answer your lookin for is 27.
The answer is H20 thank me later
Option c. 6, -5, -1, 1/2
Because the second quantum number, l, cannot be negative.
The values of l are restricted to the range 0 to n -1, which in this case is 0, 1, 2, 3, 4 and 5.
