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mina [271]
2 years ago
14

How much heat is needed to raise a 0.30 g piece of aluminum from 30.C to 150C? The specific heat of aluminum 0.900j/gC

Chemistry
1 answer:
OLEGan [10]2 years ago
8 0

Answer:

hi

Explanation:

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The food that plants produce during photosynthesis is
Marta_Voda [28]

Answer:

Glucose

Explanation:

3 0
3 years ago
. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
Which of these rocks forms from lava that cools very quickly?
den301095 [7]

The answer is D. obsidian. Or at least I think it is. Just guessing based off me playing Minecraft 6 years ago haha

4 0
3 years ago
If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow abs
Arisa [49]

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

<h3>What is entropy? </h3>

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

<h3>Formula:</h3>

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

learn more about entropy:

brainly.com/question/14131507

#SPJ1

8 0
2 years ago
How do you figure out the final temperature or the initial temperature in calorimetry.
Zolol [24]
Add the change in temperature to your substance's original temperature to find its final heat. For example, if your water was initially at 24 degrees Celsius, its final temperature would be: 24 + 6, or 30 degrees Celsius.
4 0
3 years ago
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