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Degger [83]
3 years ago
11

A football player is running with a velocity or 10 m/s. At that velocity, his momentum is 2500 kg*m/s. What is the football play

ers mass?
Physics
1 answer:
DedPeter [7]3 years ago
7 0

The mass of the football player is 250 kg.

<u>Explanation:</u>

Momentum is defined as the product of mass and velocity. So here the velocity (v) is given as 10 m/s and the momentum is given as 2500 kg m /s. So we can determine the mass (m) of the player by substituting the known terms in the formula of determining momentum as shown below.

             \text {Momentum}(p)=m \times v

As we know the value of momentum and velocity, the mass can be found as,

             m=\frac{p}{v}=\frac{2500}{10}=250 \mathrm{kg}

Thus, the mass of the football player is found to be 250 kg.

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Answer:

House and Senate.

Explanation:

declares war, regulates interstate and foreign commerce and controls taxing and spending policies.

4 0
3 years ago
PLEASEEE HELP, thank you :)
telo118 [61]

Answer:

The answer is B.

Explanation:

Given that the <em>current </em>(Ampere) in a series circuit is same so we can ignore it. We can assume that the total voltage is 60V and all the 3 resistance are different, 20Ω, 40Ω and 60Ω. So first, we have to find the total resistance by adding :

Total resistance = 20Ω + 40Ω + 60Ω

= 120Ω

Next, we have to find out that 1Ω is equal to how many voltage by dividing :

120Ω = 60V

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1Ω = 0.5V

Lastly, we have to calculate the voltage at R1 so we have to multiply by 20 (R1) :

1Ω = 0.5V

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8 0
3 years ago
If a student flicks a stationary 0.1 kg ball with 5N of force for 0.1 seconds. What is its final
Alisiya [41]

5m/s

Explanation:

Given parameters:

Mass of ball = 0.1kg

Force on the ball = 5N

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Unknown:

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Solution:

According to newton's second law "the net force on a body is the product of its mass and acceleration".

  Force = mass x acceleration      equation 1

Acceleration =

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  U is the initial velocity

  T is the time taken

 U = O since it is a stationary body;

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Input "a" into equation 1

  F = m x \frac{V}{T}

 5 = 0.1 x \frac{V}{0.1}

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learn more:

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3 0
3 years ago
Which of the following is a result of a change in pressure?
ioda
B. Exfoliation. Hope I helped you out bro.

7 0
3 years ago
A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

We know that,

m_{p}c^2=m_{np}c^2

So, E_{photon}=2mc^2+K.E_{p}+K.E_{np}

K.E_{np}=E_{photon}-(2mc^2+K.E_{p})

Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0
3 years ago
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