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Reika [66]
2 years ago
13

Ricardo is on vacation, doing some mountain climbing. He notices that the higher he goes up a mountain, the colder he feels. He

remembers his physics teacher teaching about these types of relationships. What is the type of relationship between mountain elevation and temperature?
Physics
2 answers:
Irina-Kira [14]2 years ago
8 0

Answer:

B. an inverse relationship

Explanation:

Here is the complete question

Ricardo is on vacation, doing some mountain climbing. He notices that the higher he goes up a mountain, the colder he feels. He remembers his physics teacher teaching about these types of relationships. What is the type of relationship between mountain elevation and temperature? A. a positive relationship B. an inverse relationship C. a neutral relationship D. a direct relationship

Solution

It is an inverse relationship because, as Ricardo's mountain elevation increases, he feels colder. So, as his mountain elevation increases, the temperature decreases.

Since one variable decreases while the other increases, it can only be an inverse relationship.

Let h be Ricardo's mountain elevation and T his temperature. So by inverse proportionality,

h ∝ 1/T

h = k/T

hT = k = constant

So, we have an inverse relationship and B is the answer.

cupoosta [38]2 years ago
7 0

Answer:

An inverse relationship.

Explanation:

Just took the quiz on edgenuity.

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2 years ago
Onur drops a basketball from a height of 10m on Mars, where the acceleration due to gravity has magnitude of 3.7 m/s^2. We want
denpristay [2]

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2.32 s

Explanation:

Using the equation of motion,

s = ut+g't²/2............................ Equation 1

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Note: Since Onur drops the basket ball from a height, u = 0 m/s

Then,

s = g't²/2

make t the subject of the equation,

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4 0
3 years ago
Read 2 more answers
A bird lands on a bare copper wire carrying a current of 51
nirvana33 [79]
The resistance of the piece of wire is
R= \frac{\rho L}{A}
where
\rho = 1.68 \cdot 10^{-8}\Omega m is the resistivity of the copper
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A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2 is the cross sectional area of the wire
By substituting these values, we find the value of R:
R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega

Then, by using Ohm's law, we find the potential difference between the two points of the wire:
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7 0
3 years ago
As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds
lora16 [44]

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}-a*t

where:

Vf = final velocity = 10 [m/s]

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t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2} -2*a*x\\

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x = distance [m]

(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]

7 0
2 years ago
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