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3 years ago

A ray of yellow light ( f = 5.09 × 1014 hz) travels at a speed of 2.04 × 108 meters per second in

1 answer:

6 0

Velocity = fλ

where f is frequency in Hz, and λ is wavelength in meters.

2.04 * 10⁸ m/s = 5.09 * 10¹⁴ Hz * λ 

(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴ Hz ) = λ 

4.007*10⁻⁷ m = λ 

The wavelength of the yellow light = 4.007*10⁻⁷ m

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Choose the 200 kg refrigerator. Set the applied force to 400 N (to the right). Be sure friction is turned off.What is the net fo

White raven [17]

So, there should be two forces acting on the refrigerator: the applied force and the friction force.

The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.

We have an applied force of 400 N to the right, this means that:
The magnitude of the net force is 400, directed to the right.

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3 years ago

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A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal

Masteriza [31]

1) Answer D not at all

The car is not experiencing any frictional force so that implies that there is no force acting on the car once it starts motion. So, according law of inertia, the car will continue to move and no other force is required.

Friction force is the resistance force that opposes the motion of any object. It arises due to the contact of surfaces.

2) Answer C none

There is no force on any spaceship moving far from any planet. So, according to law of inertia the spacecraft will continue to move at same speed.

Law of inertia states that any object keeps in the state of motion or rest unless a non zero external force is applied on it.

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3 years ago

Read 2 more answers

A ball is thrown straight upward with a speed of 36 m/s. How long does it take to return to its starting point, assuming negligi

svetoff [14.1K]

Answer:

The time taken for the ball to return to the starting point is is 7.4 s

Explanation:

Given;

initial velocity of the ball, u = 36 m/s

the final vellocity at maximum height, v = 0

let time taken for the ball to reach maxmimum height = t

Time taken for the ball to return to the starting point is known as time of flight, calculated as;

$t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}$

T = (2 x 36) / 9.8

T = 7.4 s

Therefore, the time taken for the ball to return to the starting point is is 7.4 s

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3 years ago

A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 150-mL mark with 34.5°C acetone. After the flask i

8_murik_8 [283]

Answer:149.73 ml

Explanation:

Given

$\beta \ of\ acetone=1.50\times 10^{-4} ^{\circ}C^{-1}$

change in volume is given by

$\Delta V=V_{final}-V_{initial}$

$\Delta V=\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]$

$V_{final}=\nu_{initial}+\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]$

$V_{final}=150+150\times 1.50\times 10^{-4}\left [ 20-32\right ]$

$V_{final}=149.73 ml$

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3 years ago

A ray of light is moving from a material having a high indexof refraction into a material with a lower index of refraction.

luda_lava [24]

(a) Away from the normal

We can find the direction of bending of the ray of light by using Snell's equation:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where we have:

n1, n2: index of refraction of the first and second medium

$\theta_1, \theta_2$ ; angle that the incident and the refracted ray form with the normal to the surface

Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have

$n_1 > n_2$

Re-arranging Snell's law we find

$sin \theta_2 = \frac{n_1}{n_2} sin \theta_1$

since we have

$\frac{n_1}{n_2}>1$

this implies

$sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1$

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the wavelength of the light in a vacuum

n is the refractive index

The equation can be rewritten as

$\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2$

and again it can be rewritten as

$\lambda_2 = \frac{n_1}{n_2} \lambda_1$

where

$\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1$

Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency remains the same

Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.

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3 years ago