A fanis rotating at a constant 360.0 rev/min. What is the magnitude of the acceleration of a point on one of its blades 10.0 cm
from the axis of rotation?
1 answer:
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Answer:
2 revolutions
Explanation:
Assume that when she runs off the edge of the 8.3m high cliff, her vertical speed is 0. So gravitational acceleration g = 9.8m/s2 is the only thing that makes her fall down. So we can use the following equation of motion to calculate the time it takes for her to fall down:
where s = 8.3 m is the distance that she falls, t is the time it takes to fall, which is what we are looking for
Since she rotates with an average angular speed of 1.6rev/s. The number of revolutions she would make within 1.3s is
