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kakasveta [241]
3 years ago
8

Which of the following would reduce the resistance of a metal wire?

Physics
2 answers:
Dmitry [639]3 years ago
8 0

Answer:

increasing its thickness

Explanation:

there are four major factors that affect the resistance of a metal wire, they are;

1. the length of the wire: the longer the length of a wire the higher the resistance

recall R=ρL/A

the above equation shows a direct relation between resistance and length

2. the temperature of the wire: the higher the temperature of a wire when heated up, the higher the resistance of the wire

3. the thickness or width of the wire: the higher the thickness the lower the resistance.

from the equation in 1 above, there is an inverse relationship between resistance and area(diameter inclusive) of a wire

4. the material of the wire: different wires have different values of resistivity(ρ). steel  shows higher levels of resistivity than copper

therefore, increasing thickness reduces resistance

Lady_Fox [76]3 years ago
3 0
All of the above can affect the resistance of a metal
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19.1 deg

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4 0
3 years ago
Suppose an electron is trapped within a small region and the uncertainty in its position is 24.0 x 10-15 m. What is the minimum
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Answer:

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  • Uncertainty in momentum (∆P) = ?
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\longrightarrow \:  \:  \sf\Delta x .\Delta p =  \dfrac{h}{4\pi}

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} {4 \times  \frac{22}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} { \frac{88}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34} \times 7} { 8 }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 8  \times 24 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 192 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34}  \times  {10}^{15} } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 2}  \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 21}   } { 192}

\longrightarrow \:  \:  \sf\Delta p = 22.822\times  {10}^{ - 21}

\longrightarrow \:  \:  \sf\Delta p = 2.2822 \times  {10}^{1} \times  {10}^{ - 21}

\longrightarrow \:  \: \underline{ \boxed{ \red{  \bf\Delta p = 2.2822 \times  {10}^{ - 20}  \:  kg/ms}}}

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