Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
tal data provided.
A + B yields products
Trial [A] [B] Rate
1 0.15 M 0.12 M 1.3 × 10-2 M/min
2 0.30 M 0.12 M 2.6 × 10-2 M/min
3 0.15 M 0.24 M 5.2 × 10-2 M/min
A + B yields products
Trial [A] [B] Rate
1 0.15 M 0.12 M 1.3 × 10-2 M/min
2 0.30 M 0.12 M 2.6 × 10-2 M/min
3 0.15 M 0.24 M 5.2 × 10-2 M/min
1 answer:
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Answer:
80.92, Krypton
Explanation:
<u>What is effusion?</u>
• It is a process where gas escapes through a pinhole (a very small hole) into a region of low pressure or vacuum
<u>Graham's law of effusion of </u><u>gas</u>
• states that at a given constant temperature and pressure, the rate of effusion of gases is inversely proportional to the square root of their molar masses
<u>Calculations</u>
Nitrogen exist as N₂ at room temperature, thus its molar mass is 2(14)= 28.
Let the rate and molar mass of unknown gas be Rate₂ and M₂ respectively.
Since N₂ effuses 1.7 times as fast as the unknown gas,
Rate₁= 1.7(Rate₂)
Square both sides:
Multiply both sides by 28:
2.89(28)= M₂
M₂= 80.92
<u>Identity of </u><u>gas</u>
The molar mass of 80.92 lies between Bromine and Krypton. However since Bromine exist as Br₂, the value of it's molar mass would be 159.8 instead. Hence, Bromine is eliminated.
If the gas is a diatomic element, the atomic weight is 80.92 ÷2= 40.46. Thus, we are now considering if Argon could be its identity. However, Argon is a noble gas and will not exist as a diatomic element. Argon is therefore eliminated too.
Thus based on the above reasoning, its probable identity is Krypton.
