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Solnce55 [7]
3 years ago
15

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen

tal data provided.
A + B yields products
Trial [A] [B] Rate
1 0.15 M 0.12 M 1.3 × 10-2 M/min
2 0.30 M 0.12 M 2.6 × 10-2 M/min
3 0.15 M 0.24 M 5.2 × 10-2 M/min

Chemistry
1 answer:
murzikaleks [220]3 years ago
5 0

Answer: Rate law is, R= 6.02[A]¹[B]²

Explanation in attached image

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ahrayia [7]
Properties of a compound is completely different from their elements.

Water is composed by hydrogen and oxygen.

For example, the boiling point of oxygen is - 183 °C and hydrogen is - 253 °C, meanwhile, water has a boiling point of 100°C

Another example is when you put a burning wooden splint into oxygen, it burns more brightly. Put it in hydrogen, you may hear a "pop" sound, or even explode when large amount of hydrogen. But if u put a burning splint in water, it goes off.
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3 years ago
Consider the following equilibrium:
Ainat [17]

<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

7 0
3 years ago
What type of bond occurs between tow nonmetals.
Aleksandr-060686 [28]

Answer:

covalent bonds............

6 0
2 years ago
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Why does the pressure inside a container of gas increase?
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Pressure is a scientific parameter that allows us to determine the amount of force being exerted per unit area. The increase in the pressure inside a container containing a gas may be brought upon by the decrease in volume, increase in temperature, or merely by additional of more gas molecules. 
3 0
3 years ago
The reaction between carbon tetrachloride, CCl4, and water, H2O, to form carbon dioxide, CO2, and hydrogen chloride, HCl, has a
Ber [7]

Answer:

1) a) It is a slow reaction kinetically.

2) a) It is a catalyst.

3) c) It lowered the activation energy of the reaction.

Explanation:

<em>1) The reaction between carbon tetrachloride, CCl₄, and water, H₂O, to form carbon dioxide, CO₂, and hydrogen chloride, HCl, has a ΔG° value of -232 kJ/mole, and so is thermodynamically favored. But when you mix carbon tetrachloride with water, no change is observed. What is a possible explanation for this? </em>

<em>a) It is a slow reaction kinetically.</em>  TRUE. This is the most likely explanation of why no change is observed.

<em>b) The activation energy of the reaction is too small.</em>  FALSE. Slow reactions have a large activation energy.

<em>c) The reaction is not spontaneous. </em> FALSE. ΔG° < 0 so the reaction is spontaneous.

<em>d)The reaction is not favored thermodynamically.</em> FALSE. ΔG° < 0 so the reaction is favored thermodynamically.

<em>2) What word best describes the role that the palladium plays in the reaction between propene and hydrogen above?</em>

It is a catalyst because it increases the rate of the reaction without being altered by the end of the reaction.

<em>3) What did the palladium do to increase the rate of the reaction between the propene and hydrogen? </em>

<em>a)It changed the thermodynamic equilibrium.</em>  FALSE. Catalysts don't affect equilibrium

<em> b)It made the Gibbs free energy of the reaction more positive.</em>  FALSE. Catalysts don't affect Gibbs free energy.

<em>c)It lowered the activation energy of the reaction.</em>  TRUE. According to the Arrhenius equation, the lower the activation energy, the higher the rate constant, and the higher the rate of reaction. This is how catalysts act.

<em>d)It increased the activation energy of the reaction.</em> FALSE.

7 0
3 years ago
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