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Solnce55 [7]
3 years ago
15

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen

tal data provided.
A + B yields products
Trial [A] [B] Rate
1 0.15 M 0.12 M 1.3 × 10-2 M/min
2 0.30 M 0.12 M 2.6 × 10-2 M/min
3 0.15 M 0.24 M 5.2 × 10-2 M/min

Chemistry
1 answer:
murzikaleks [220]3 years ago
5 0

Answer: Rate law is, R= 6.02[A]¹[B]²

Explanation in attached image

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What is the number of copper atom in one naira coin which weight is 7.3g a sum of the material is 86%
Step2247 [10]

Answer:

5.9x10²² atoms of Cu are in one naira coin

Explanation:

To solve this question we need to find the mass of Copper. Then, using its molar mass (Cu = 63.546g/mol) we must find the moles of Cu and its atoms using Avogadro's number:

<em>Mass Cu:</em>

7.3g * 86% = 6.278g is the mass of Cu.

<em>Moles Cu:</em>

6.278g * (1mol / 63.546g) = 0.099moles Cu

<em>Atoms Cu:</em>

0.099moles Cu * (6.022x10²³atoms / 1mol) =

<h3>5.9x10²² atoms of Cu are in one naira coin</h3>
4 0
3 years ago
How many atoms are in 25.00 g of B?
klio [65]

Answer:

There are 1.393 x 10²⁴ atoms in 25.00 g of B.

Explanation:

Hey there!

We are given a value, in grams, that we need to convert to a number of atoms.

We can convert grams to atoms by using Avogadro's Number (N_A). This number is equivalent to 6.022 \times 10^{23}.

This number can be used to convert any values to:

  • atoms
  • molecules
  • formula units
  • moles

In order to do this problem, we will need to use dimensional analysis (DA). This process allows us to convert from grams to atoms.

We need to set up our ratios in order to work this out. We can use a periodic table to help us through this next part of the problem.

<u>1. Locating the number of moles of B in the sample</u>

We first need to find the amount of moles of boron (B) there are in the sample.

Checking a periodic table, the atomic mass in atomic mass units (amu) is 10.81 amu.

  • Atomic mass units can easily be converted to grams and these units can be used interchangeably.

Therefore, for each atom of boron, it weighs 10.81 grams to us. This is equivalent to the mass of one mole of boron.

To find the number of moles, we have two possible ratios we can use:

  • \displaystyle \frac{1 \ mole \ B}{10.81 \ grams \ B}
  • \displaystyle \frac{10.81 \ grams \ B}{1 \ mole \ B}

These ratios mean the same thing, but we need to convert our final unit to moles.

We are given a sample in grams, and when dividing our units, we need to keep moles.

Since the first portion of our expression is in grams, we need to have grams in the bottom of our expression.

  • \displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}}

We can now simplify the expression. Our <u>grams B</u> unit will cancel out, so we are therefore left with <u>moles B</u> remaining.

<u>2. Locating the number of atoms in the sample</u>

Now with our equation, we can convert our number of moles that would be solved if we stopped with the above. However, we need to convert to atoms.

We use Avogadro's number and create a ratio with that of moles.

  • \displaystyle \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}
  • \displaystyle \frac{1 \text{mole B}}{6.022 \times 10^{23} \text{atoms}}

We need to cancel out our moles and end with atoms, so we must have moles in the denominator. Therefore, we use the first ratio.

Using our previous expression, we multiply by this new ratio and solve the expression.

  • \displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}} \ \times \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}

This expression can now be operated. You will need a calculator to perform this calculation.

<u>Our numerator is:</u>

  • [(25.00 \times 1 \times (6.022 \times 10^{23})]

Plugging this into a calculator, we get:

  • 1.5055 \times 10^{25}

<u>Our denominator is:</u>

  • (1 \times 10.81 \times 1)

This simplifies to:

  • 10.81

<u>Dividing our numerator and denominator:</u>

  • <u />\displaystyle \frac{1.5055 \times 10^{25}}{10.81}<u />

Plugging this into a calculator, we get:

  • 1.392691952 \times 10^{24}

<u>3. Simplifying with significant figures</u>

Now, we need to take into account that we have significant figures. We are given this original value:

  • 25.00

This value has four significant figures, which means we need to round our value we received above to four significant figures.

  • \approx 1.393

Our units are added as well as our scientific notation:

  • 1.393 \times 10^{24} \ \text{atoms of B}

Therefore, our final answer is choice A.

8 0
3 years ago
A substance that speeds up a chemical reaction without being part of the chemical change, itself:
allochka39001 [22]
It is known as a catalyst 
6 0
3 years ago
Can somebody answer this question for me it might be easy for you answer part 1,2,and 3
jonny [76]

Answer:

hey love! what is the question??

8 0
3 years ago
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Define the term valence electron and explain how to find the number of valence electrons in family one and family 2.
goblinko [34]
Valence Electron is the outermost electrons, family(Alkali) 1 has 1 valence electrons and family(Alkaline) 2 has 2 valence electrons.

Hope this helps
8 0
3 years ago
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