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The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
<h3>How to calculate pH?</h3>
The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:
pH = pka + log ([A-]/[HA])
Where;
- A- = conjugate base
- HA = weak acid
pH = pKa + log([F-]/[HF])
pH = 3.14 + log(1/0.35)
pH = 3.14 + 0.4559 = 3.595
Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
Learn more about pH at: brainly.com/question/15289741
If we are talking about moles then the answer to that is 0.22
Answer:
A. Calcium chloride (CaCI2)