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balandron [24]
3 years ago
9

Part iii. Is the dissolution reaction of ammonium nitrate enthalpy favored?

Chemistry
1 answer:
lesya [120]3 years ago
3 0

Answer:

No, it is not enthalpy favored since the chemical system gains energy.

Explanation:

The dissolution of ammonium nitrate in water is an endothermic process.

Endothermic process requires the system to gain energy to can dissolve the particles in water.

So, the reaction is not enthalpy favored.

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A mineral that contains silicon and oxygen
Sergio [31]
<span>Hey there!
Great question:)

Answer:Silicates, this is a mineral that contains silicon and oxygen!

I hope this helps;)
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3 0
3 years ago
3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic e
mezya [45]

Answer: Hydrogen molecules will have greatest average speed.

Explanation:

The formula for average speed is  :

\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}

R = gas constant  

T = temperature  

M = Molecular Mass

Now putting all the values:

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}

\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8

Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed

8 0
3 years ago
Is gamma rays blocked very easily
Leto [7]
No, since they are the strongest type of ray only elements that are dense can block them.
5 0
4 years ago
A student measures the mass of a 10m^3 block of gold to be 500 kg what is the density of the gold
Anuta_ua [19.1K]

Answer:

d = 50 kg/m³

Explanation:

density = \frac{mass}{volume}

mass = 500 kg

volume = 10m³

\frac{500}{10} = 50

d = 50 kg/m³

8 0
3 years ago
(c) Assume you have an equilibrium mixture of [A], [B], and [C] at 298K and that the
djyliett [7]

Answer:

Explanation:

1. The amount of CaCO3 must be so small that  

P

CO

2

 is less than KP when the CaCO3 has completely decomposed. In other words, the starting amount of CaCO3 cannot completely generate the full  

P

CO

2

 required for equilibrium.

3. The change in enthalpy may be used. If the reaction is exothermic, the heat produced can be thought of as a product. If the reaction is endothermic the heat added can be thought of as a reactant. Additional heat would shift an exothermic reaction back to the reactants but would shift an endothermic reaction to the products. Cooling an exothermic reaction causes the reaction to shift toward the product side; cooling an endothermic reaction would cause it to shift to the reactants’ side.

5. No, it is not at equilibrium. Because the system is not confined, products continuously escape from the region of the flame; reactants are also added continuously from the burner and surrounding atmosphere.

7. Add N2; add H2; decrease the container volume; heat the mixture.

9. (a) ΔT increase = shift right, ΔP increase = shift left; (b) ΔT increase = shift right, ΔP increase = no effect; (c) ΔT increase = shift left, ΔP increase = shift left; (d) ΔT increase = shift left, ΔP increase = shift right.

11. (a)  

K

c

=

[

CH

3

OH

]

[

H

2

]

2

[

CO

]

; (b) [H2] increases, [CO] decreases, [CH3OH] increases; (c), [H2] increases, [CO] decreases, [CH3OH] decreases; (d), [H2] increases, [CO] increases, [CH3OH] increases; (e), [H2] increases, [CO] increases, [CH3OH] decreases; (f), no changes.

13. (a)  

K

c

=

[

CO

]

[

H

2

]

[

H

2

O

]

; (b) [H2O] no change, [CO] no change, [H2] no change; (c) [H2O] decreases, [CO] decreases, [H2] decreases; (d) [H2O] increases, [CO] increases, [H2] decreases; (f) [H2O] decreases, [CO] increases, [H2] increases. In (b), (c), (d), and (e), the mass of carbon will change, but its concentration (activity) will not change.

15. Only (b)

17. Add NaCl or some other salt that produces Cl− to the solution. Cooling the solution forces the equilibrium to the right, precipitating more AgCl(s).

19. (a)

Hope this helps :)

3 0
3 years ago
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