To answer this question, we will use the equation of Clausius-Clapeyron which can be written as follows: ln(P1/P2) = ΔH/R x (1/T2 - 1/T1)
Now, let's check the parameters in this equation: P1 is the normal pressure of the vapor which is 4.24 kPa T1 is the boiling point at this pressure which is 293 K ΔH is the heat of vaporization given as 39.9 kJ/mol T2 is given as 355.3 K and we need to calculate P2
Substitute in the equation to get P2 as follows: ln(4.24/P2) = 39.9/0.008314 x (1/355.3 - 1/293) P2 = 101.2 kPa = 0.998766 atm