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AVprozaik [17]
3 years ago
5

You back packed for a distance of 15.75 miles today. You back packed at an average speed of 1.26 miles per hour, how long did yo

u spend backpacking
Mathematics
1 answer:
Anna [14]3 years ago
7 0

Let us first concentrate and write down all the information's given in the question. Based on these information's the answer to the question can be easily deduced.
Distance for which back packing was done = 15.75 miles
Average speed of back packing = 1.26 miles/hour
Since
Speed = Distance/Time
Time = Distance/speed
Time spend for back packing = 15.75/1.26 hour
                                               = 12.5 hour
So the total time taken for back packing is 12.5 hours. I hope this is the answer you were looking for and the procedure is clear to you.
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What is the midpoint of the line segment with endpoints
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Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
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Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

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H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

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Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

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The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

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Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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