Answer: 5
Step-by-step explanation:
Range = highest value - lowest value
The highest value from the data set given = 1
The lowest value = -4
Therefore :
Range = 1 - (-4)
Range = 1 + 4
Range = 5
Answer:
1.
T mBAC = mB'A'C'
F 2mABC = mA'B'C'
F BC = 2B'C'
T 2XA = XA'
2
D'(-2/3; -1)
E'(-1;1)
F'(1;1)
G'(1;-1)
3
the centre is L(0;-2)
the scale factor is 4
length J'K' = 4JK
the measure of L is equal the measure of L'
<u>the</u><u> </u><u>table</u><u>:</u>
K(4;2) 4 4 16 16 0+16 -2+16 K'(16;14)
we are given
distance=6.7 furlongs
(a) In rods
we know that

we can multiply both sides by 6.7

..............Answer
(b) In chains
we know that

we can multiply both sides by 6.7

..............Answer
Can you make the question more clear
Solution :
Let x be student will be left handed
P = 0.09
Using the normal approximation to binomial distribution,
a). n = 108,
μ = np = 9.72


= 2.9741
Required probability,
P(x=8) = P(7.5 < x < 8.5)


Using z table,
= P(z<-0.41)-P(z<-0.75)
= 0.3409-0.2266
= 0.1143
b). P(x=12) = P(11.5 < x < 12.5)


Using z table,
= P(z< 0.94)-P(z< 0.60)
= 0.8294 - 0.7257
= 0.1006