Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a f<span><span>irst-quadrant graph showing a ray from the origin through the points
(2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis
label is Plant growth in inches.</span>
The rate of relationship A is given by the slope of the graph as follows:

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.
For table A.
Time (weeks) 3 6 8 10
Plant growth (in.) 2.25 4.5 6 7.5

For table B.
Time (weeks) 3 6 8 10
Plant growth (in.) 4.8 9.6 12.8 16
</span><span><span>

</span>
For tabe C.
Time (weeks) 3 4 6 9
Plant growth (in.) 5.4 7.2 10.8 16.2
</span><span>
For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9</span>
<span>

</span>
Therefore, the table that could represent Relationship B is table A.
Answer:
y = 2x + 7
The m in the equation is the slope and the b is always the y-intercept.
Answer:
Given MC = 4
AN = 14
To Find, the length of NB
Step-by-step explanation:
AB is a line which has midpoint “C”. Now the line is divided into two equal portion AC and CB.
The AC has midpoint “M” and MC is 4, so AM will also be 4.
N is the midpoint of CB. So, CB = CN + NB
Now we know AC = AM + MC = 4 + 4 =8
Given, AN = 14
AN = AC + CN
14 = 8 + CN
CN = 6
Since N is the midpoint of CB then, CN = NB
Therefore, the NB is 6
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).
First, we find the midpoint M using the midpoint formula:

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if
m and
n are the slopes of 2 parallel lines, then
mn=-1.
The slope of WX is

.
Thus, the slope n of the perpendicular line is

.
The equation of the line with slope

containing the point M(0, -1) is given by:




Answer: 5x-3y-3=0
Answer: 12≠6
False
Step-by-step explanation: