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Helen [10]
2 years ago
6

What is the current in a 120V circuit if the resistance is 20Ω?

Physics
1 answer:
Kaylis [27]2 years ago
6 0

We have: I=\frac{U}{R}=\frac{120}{20}=6A

ok done. Thank to me :>

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Can you tell Which body part does not help in the perception and production of sound in humans?
Korolek [52]
Your lungs aren’t the ones that make the sound
6 0
3 years ago
a car slows down from 22 m/s to 3 m/s at a constant rate of 3.5 m/s squared. how many seconds are required before the car is tra
Stolb23 [73]

Answer:

9.05 s

Explanation

v=u+at

6 0
3 years ago
A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is
mamaluj [8]

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:

ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33  1/3 rev/m so

the frequency 33.33/60=0.55 Hz

then w=2*π*0.55=3.45 rad/s

Finally the centripetal acceleration at differents radii results equal:

r= 0.05 m  ac=3.45^2*0.05=0.50 m/s^2

r=0.1  ac=3.45^2*0.1=1.20 m/s^2

r=0.14 ac=3.45^2*0.14=1.66 m/s^2

4 0
3 years ago
Ball A is negatively charged and ball B is electrically neutral. What happens to the charges of both balls when they come into c
tresset_1 [31]

Explanation:

They will repel, thus made of electrical conductor.

5 0
2 years ago
A 425-g piece of metal at 100°C is dropped into a 100-g aluminum cup containing 500 g of water at 15°C. The final temperature of
yKpoI14uk [10]

The specific heat of the metal, assuming no heat is exchanged with the surroundings is 2140 J/(kg•K).

<h3>Specific heat capacity of the metal</h3>

The specific heat capacity of the metal is determined from the principle of conservation of energy.

energy lost by the metal = energy gained by aluminum + energy gained by water

Q = mcΔθ

where;

  • m is mass (kg)
  • c is specific heat capacity
  • Δθ is change in temperature

0.425c(100 - 40) = 0.1(900)(40 - 15) + 0.5(4186)(40 - 15)

25.5c = 2250 + 52,325

c = 54,575/25.5

c = 2140 J/(kg•K)

Learn more about specific heat capacity here: brainly.com/question/21406849

#SPJ1

5 0
1 year ago
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