Answer:
ΔG° = -533.64 kJ
Explanation:
Let's consider the following reaction.
Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)
The standard Gibbs free energy (ΔG°) can be calculated using the following expression:
ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)
where,
ni are the moles of reactants and products
ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products
ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)
ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)
ΔG° = -533.64 kJ
Products
Chemical reactions are characterized by the formation of new products, and the making and breaking of strong chemical bonds.
C-12? (6 protons) C-13? (6 protons) C-14? (6 protons)
Answer:
9.42g/cm3
Explanation:
Data obtained from the question include the following:
Mass of the metal = 24.50g
Volume of metal = 2.6 ml = 2.6cm3
Density =..?
The density of a substance is defined by the mass of the substance per unit volume of the substance. It is represented mathematically as:
Density = Mass /volume
With the above formula, we can obtain the density of the metal as follow:
Density = Mass/volume
Density = 24.50g/2.6cm3
Density = 9.42g/cm3