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tekilochka [14]
2 years ago
10

When 47.2 J of heat is added to 13.4 g of a liquid, its

Chemistry
1 answer:
leva [86]2 years ago
8 0

Answer: 2.02 J/g°C

Explanation:

To find the heat capacity, we have to manipulate the equation for heat.

q=mCΔT becomes C=q/(mΔT) to find heat capacity. Since we are given our values, we can plug in to find C.

C=\frac{47.2J}{13.4g*1.74°C}

*Please ignore the capital A in front of the °C. In order to have ° in the equaiton, the A pops up.

C=2.02J/g°C

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