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tekilochka [14]
2 years ago
10

When 47.2 J of heat is added to 13.4 g of a liquid, its

Chemistry
1 answer:
leva [86]2 years ago
8 0

Answer: 2.02 J/g°C

Explanation:

To find the heat capacity, we have to manipulate the equation for heat.

q=mCΔT becomes C=q/(mΔT) to find heat capacity. Since we are given our values, we can plug in to find C.

C=\frac{47.2J}{13.4g*1.74°C}

*Please ignore the capital A in front of the °C. In order to have ° in the equaiton, the A pops up.

C=2.02J/g°C

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A solution labeled "0.105 M NaOH" would contain ______________ moles of NaOH in each liter of solution.
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Answer:

A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Explanation:

The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.

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Volume of solution in L = 1 L

0.105 = Number of moles of solute × 1

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Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

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Which is a property of potassium (K)? O A. It is dull and brittle. O B. It is not reactive. O C. It is white and hard. O D. It i
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D. It is extremely reactive.​

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