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Novosadov [1.4K]
3 years ago
13

A compound with the empirical formula ch2 has a molar mass of 98 g/mol what is the molecular formula for this compound ?

Chemistry
1 answer:
madam [21]3 years ago
7 0
Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1

Let n = moles required for CH₂.
Then
nCH₂ = 98
n(12 + 2*1) = 98
14n = 98
n = 7

Answer: The molecular formula is 7CH₂

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slavikrds [6]

Solution :

Comparing the solubility of silver chromate for the solutions :

$0.10 \ M \ AgCH_3COO$    -----     Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$   ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$   -----   Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$   -----   Similar solubility as in the pure water

The silver chromate dissociates to form :

$AgCrO_4 (s) \rightleftharpoons 2Ag^+ (aq) +CrO_4^{2-}(aq)$

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Both AgCH_3COO and $KCH_3COO$ are neutral mediums, so they do not affect the solubility.

 

4 0
2 years ago
What is the mole ratio of NH3 to N2?
Ksenya-84 [330]
To answer this question a balanced chemical equation is necessary. The correct equation is: N2 + 3H2 = 2NH3
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Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

2) The given reaction is:

4Li(s) + O₂ (g) → 2 Li₂O(s)

3) Determine the oxidation states of each atom:

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O₂ (g): oxidation state = 0 (since it is alone)

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O in Li₂O -2

That because 2× (+1) - 2 = 0.

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O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0
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