All categories

3 years ago

Describe the circumstances for which the output work would equal the input work in a machine

1 answer:

3 0

That's only possible if there is absolutely zero friction in the machine.

In the real world, we can come close, with lubricants (oil, grease) and
streamlining, but we can never build anything with totally zero loss of
energy inside.

You might be interested in

1. What net force is required to accelerate a car at a rate of 2 m/s2 if the car has a mass of 3,000 kg?

nataly862011 [7]

Answer:

Net force required to accelerate the car is 6000 N

Explanation:

Force is calculated by the equation, F = Mass × Acceleration

This is based on Newton's Second Law of Motion which states that the force acting on an object is its mass times the acceleration of the object.

Here, mass = 3000 kg and acceleration = 2 m/s²

⇒ Force = Mass × Acceleration

= 3000 × 2 = 6000 N

⇒ F = 6000 N

⇒ M = 3000 kg

⇒ a = 2 m/s²

7 0

3 years ago

Whats the role of the suns gravity in the solar system

Rasek [7]

The suns gravity pulls on the planets and keeps them in place. Its gravitational pull puts them in orbit around the sun

5 0

4 years ago

Read 2 more answers

The speed of a car is increased uniformly from 11 meters per second to 19 meters per second. The average speed of the car during

dsp73

15 m/s average is (11+19)/2

6 0

4 years ago

. A block of mass 4.0 kg on a spring has displacement as a function of time given by, x (t) = (1.0 cm) cos [(2.0 rad/s) t + 0.25

svlad2 [7]

Answer and Explanation:

1. Evaluate the function x(t) at t=0.5

$x(t)=1cos(2t+0.25)\\x(0.5)=cos(2*0.5+0.25)=cos(1+0.25)=cos(1.25)=0.3153223624\approx0.31cm$

2. The period of motion T can be calculated as:

$T=\frac{2\pi}{\omega}$

Where:

$\omega=2rad/s$

So:

$T=\frac{2\pi}{2}=\pi\approx3.14s$

3. The angular frequency can be expressed as:

$\omega=\sqrt{\frac{k}{m} }$

Solving for k:

$k=(\omega)^2*m=(2)^2*4=4*4=16\frac{N}{m}$

4. Find the derivate of x(t):

$\frac{dx}{dt} =v(t)=-2sin(2t+0.25)$

Now, the sine function reach its maximum value at π/2 so:

$2t+025=\frac{\pi}{2}$

Solving for t:

$t=\frac{\frac{\pi}{2} -0.25}{2} =0.6603981634s$

Evaluating v(t) for 0.6603981634:

$v(0.6603981634)=-2sin(2*0.6603981634+0.25)=-2sin(\frac{\pi}{2} )=-2*1=2$

So the maximum speed of the block is:

$v(0.6603981634)=2cm/s=0.02m/s$

In the negative direction of x-axis

5. The force is given by:

$F=kx$

The cosine function reach its maximum value at 2π so:

$2t+0.25=2\pi$

Solving for t:

$t=\frac{2\pi-0.25}{2} =3.016592654s$

Evaluating x(t) for 3.016592654:

$x(3.016592654)=cos(2*3.016592654+0.25)=cos(2\pi)=1cm=0.01m$

Therefore the the maximum force on the block is:

$F=16*0.01=0.16N$

6 0

3 years ago

Is water wet? I think it is but people think it isn’t

alexandr402 [8]

Water isn't wet. Wetness is a description of our experience of water; what happens to us when we come into contact with water in such a way that it impinges on our state of being. We or our possessions get wet

4 0

3 years ago

Read 2 more answers