The cost of renting a car is modeled by a linear relationship. The cost for two days is $128, and the cost for five days is

Find the equation of a line that is PERPENDICULAR to y = 1/3 x -2 & passes through the point ( 3, 2 ). (CHECK PIC FOR ANSWER

densk [106]

Answer:

The answer to your question is the letter b) y = -3x + 11

Step-by-step explanation:

Data

Original line y = 1/3x - 2

Point = (3, 2)

New line = ? (perpendicular)

Process

1.- Get the slope of the original line

The slope is the coefficient of the x in the line equation.

y = 1/3x - 2

slope = m = 1/3

2.- Find the slope of the new line

new slope = -3 (because the lines are perpendicular)

3.- Find the equation of the new line

y - y1 = m(x - x1)

x1 = 3 y1 = 2

-Substitution

y - 2 = -3(x - 3)

-Simplification

y - 2 = -3x + 9

y = -3x + 9 + 2

-Result

y = -3x + 11

3 0

4 years ago

How to solve this question

AlexFokin [52]

Divide 141 by 3, that’s 47. Now subtract 47 from 141 and you get 94. 94 of the figures are not sports related. The answer is B.

7 0

3 years ago

Read 2 more answers

What are the 5 infinitives?

Ymorist [56]

The five types of infinitives are full infinitives, bare infinitives, split infinitives, continuous infinitives , and perfect continuous infinitive.

Explanation:

Types of infinitives:

Five types of infinitives are as follow:

Full infinitives : Add 'to' Infront of the verb to complete the the situation.

Bare infinitives: here " to" get omitted from the sentence.

Split infinitives : Here adjectives slides between infinitives marker.

To hear : full infinitives changes to split infinitives : to slowly hear.

Continuous infinitives: Action going for certain period of required time.

Example : to be missing

Perfect continuous infinitives: prior to a time :

Example : to have seen

Therefore, there are are five types of infinitives .

Learn more about infinitives here

brainly.com/question/1219442

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5 0

1 year ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

5x + qy, when x=8,y=11

Nataliya [291]

Answer:

40+11q

Step-by-step explanation:

5x+qy

5(8)+q(11)=40+11q

4 0

3 years ago