1.CO2 - carbon dioxide
<span>2.H2O - water </span>
<span>3.NaCl - salt </span>
<span>4.H2 - hydrogen</span>
The question is incomplete, the complete question is:
A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.
Answer:
0.153M of anions
Explanation:
First we calculate the concentration of the solution. From m/M= CV
m=given mass, M= molar mass, C =concentration of solution, V= volume of solution
Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1
0.4g/157.5gmol-1= C×50/1000
C= 2.54×10-3/0.05= 0.051M
But 1 mole of VCl3 contains 3 moles of anions
Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions
Answer:
10.875 miles
So 87 minutes
.125 miles per minute
So just multiply int his case
87*.125
You’d get 10.875
Answer:
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Explanation:
Answer:
Sodium and Magnesium
Explanation:
The elements in Groups 1 and 2 get more reactive as you go down the group.
This means that Sodium is more reactive than lithium and Magnesium is more reactive than beryllium.
On the periodic table, as you go down the group, the reactivity of an element increases. Especially with metals in group 1 and 2. Now Lithium is a metal of group 1, followed by Sodium, while Beryllium is a metal in group 2, followed by magnesium. That's how I picked the answers