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3 years ago

How are the testes and the ovaries similar?

Chemistry

2 answers:

enyata [817]3 years ago

4 0

I think it is “they are reproductive organs

VMariaS [17]3 years ago

3 0

They are reproductive organs

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What element is oxidized in the following reaction?

Vikentia [17]

Cu since the oxidation number of Cu is changed from 0 to +2. It means it is oxidized as per loss of two electrons.

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4 years ago

A student found the mass of the irregular solid to be 6.4 grams and the volume on the graduated cylinder rose from 6.8 mL to 7.7

Sedaia [141]

Density, Volume and Mass

3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water

level rose to the 37.4 mL mark.

a) Calculate the density of the metal (in g/mL).

b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?

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3 years ago

Identify the Lewis acid in this balanced equation: Central N is bonded above, left, and below to C H 3 and has 2 electron dots t

notsponge [240]

A chemical substance that gains or accepts electrons from others is called lewis acids. The Lewis acid in the reaction is Trihydridoboron $(\rm BH_{3}).$

<h3>What are lewis acids and bases?</h3>

For the formation of the covalent bonds the molecule or the atoms that accept or gain an electron from the other species present in the reaction are called lewis acids. The species formed after accepting electrons are called a conjugate base.

The species that donates electrons to the other species are called lewis base and the species formed after the electron donation is called a conjugate acid.

Therefore, option B. $\rm BH_{3}$ is the lewis acid as it gains an electron.

Learn more about lewis acids here:

brainly.com/question/19031282

6 0

3 years ago

Which of the following chemical bonds holds together atoms in an acid?

Nat2105 [25]

I believe it is covalent bonds not 100% sure

3 0

3 years ago

Calculate Horxn for the following reaction:H3AsO4(aq) + 4 H2(g) --> AsH3(g) + 4 H2O(l)(Hof [AsH3(g)] = 66.4 kJ/mol; Hof [H

Juli2301 [7.4K]

Answer:

The Standard enthalpy of reaction: $\Delta H_{r}^{\circ } = (-172.2) \, kJ$

Explanation:

Given- Standard Heat of Formation:

$\Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)]$ = -904.6 kJ/mol

$\Delta H_{f}^{\circ } [H_{2}(g)]$ = 0 kJ/mol,

$\Delta H_{f}^{\circ } [AsH_{3}(g)]$ = +66.4 kJ/mol

$\Delta H_{f}^{\circ } [H_{2}O(l)]$ = -285.8 kJ/mol

Given chemical reaction: H₃AsO₄(aq) + 4H₂(g) → AsH₃(g) + 4H₂O(l)

The standard enthalpy of reaction: $\Delta H_{r}^{\circ }$ = ?

To calculate the Standard enthalpy of reaction ( $\Delta H_{r}^{\circ }$ ), we use the equation:

$\Delta H_{r}^{\circ } = \sum \nu .\Delta H_{f}^{\circ }(products)-\sum \nu .\Delta H_{f}^{\circ }(reactants)$

$\Delta H_{r}^{\circ } = [1 \times \Delta H_{f}^{\circ } [AsH_{3} (g)] + 4 \times \Delta H_{f}^{\circ } [H_{2}O(l)]] - [1 \times \Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)] + 4 \times \Delta H_{f}^{\circ } [H_{2}(g)]$

$\Rightarrow \Delta H_{r}^{\circ } = [1 \times (+66.4\,kJ/mol) + 4 \times (-285.8\,kJ/mol) ] - [1 \times (-904.6\,kJ/mol) + 4 \times (0\,kJ/mol)]$

$\Rightarrow \Delta H_{r}^{\circ } = [-1076.8\, kJ] - [-904.6\,kJ]$

$\Rightarrow \Delta H_{r}^{\circ } = (-172.2 \, kJ)$

Therefore, the Standard enthalpy of reaction: $\Delta H_{r}^{\circ } = (-172.2) \, kJ$

5 0

4 years ago