Which of these units of pressure are equal in size
1 answer:
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Answer:
pH = 3.34
Explanation:
We can calculate the pH using <em>Henderson-Hasselbach's equation</em>:
- pH = pKa + log
for HCOOH, pKa = 3.75.
We can <u>calculate [HCOO⁻] and [HCOOH]</u> using the<em> given number of moles for each one and the final volume</em>:
- Final Volume = 44.12 mL + 250 mL = 294 mL
- 294 mL / 1000 = 0.294 L
- [HCOO⁻] = 0.036 mol / 0.294 L = 0.122 M
- [HCOOH] = 0.091 mol / 0.294 L = 0.310 M
Then we proceed to <u>calculate the pH</u>:
- pH = 3.75 + log
- pH = 3.34
Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
Learn more: brainly.com/question/2510654
