5. Ionic
6.Ionic
7. Both
8. Covalent
I could do this in my sleep
2N2O5(g)----> 4NO2(g) + O2(g)
<span>[N2O5]i (M) Initial Rate(M^-1 s^-1) </span>
<span>0.093 4.84x10^-4 ---- (1) </span>
<span>0.186 9.67x10^-4 ----- (2) </span>
<span>0.279 1.45x10^-3 ----- (3) </span>
<span>From equation (1) & (2) it is evident that when [N2O5}i is doubled the initial rate is doubled, which implies the rate is directly proportional to [N2O5]. Similarly comparing equation (1) & (3) we observe that when [N2O5] is tripled the rate is also tripled. Hence the rate equation is </span>
<span>Rate = k [N2O5] </span>
<span>Using the data of any equation, say (1), we get </span>
<span>4.84x10^-4 = k x 0.093 </span>
<span>OR k = 4.84x10^-4/0.093 = 5.2 x 10^-3 s-1 </span>
<span>Hence the rate law is </span>
<span>Rate = 5.2 x 10^-3 s-1[N2O5]</span>
Answer:
1) 1,1,1-trichloropropane
2) 1,1,2-trichloropropane
3) 1,2,2-trichloropropane
4) 1,2,3-trichloropropane
Explanation:
For this question, we must remember that isomers are molecules that have the <em>same formula but different structure</em>s. For the formula we can draw a <u>linear chain of three carbons</u> and change the position of the chlorine atoms in the carbon chain.
With this in mind, if we put all the chlorine atoms on the same carbon we will get <u>1,1,1-trichloropropane</u>. If we change an atom from chlorine to carbon 2 we will obtain <u>1,1,2-trichloropropane</u>. If we move another chlorine atom to carbon two we will get <u>1,2,2-trichloropropane</u>. Finally, if we put a chlorine atom in each carbon we will obtain <u>1,2,3-trichloropropane</u>.
See figure one for further explanations
I hope it helps!
For example, silicon has 14 protons and 14 neutrons. Its atomic number is 14 and its atomic mass is 28.
The complete question is as follows: Barium chloride (BaCl2) emits a green color when flame tested. What can be said about the wavelength of light it emits? Select all that apply.
A) The thermal energy is transferred to the outer electrons of the barium ions.
B) The electrons gain enough energy to excite them to a higher energy level.
C) The electrons drop back down to their ground state, gaining energy.
D) The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Answer: The following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Explanation:
As barium chloride is emitting green color when flame tested. This means that thermal energy is being transferred to the outer electrons of barium ions.
A visible light is emitted by a substance when its electrons move from a region of higher energy level to lower energy level. This is because energy is given off by the electrons when they move in a lower region.
This is only possible when the electrons gain enough energy to excite them to a higher energy level.
Also, the electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Thus, we can conclude that following can be said about the wavelength of light that Barium chloride emits:
- The thermal energy is transferred to the outer electrons of the barium ions.
-
The electrons gain enough energy to excite them to a higher energy level.
- The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.