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Anuta_ua [19.1K]
3 years ago
15

How many atoms and molecules are present in 124 gram of phosphorus

Chemistry
1 answer:
Ierofanga [76]3 years ago
6 0
31g phosphorus has 6.02×10^23 atoms
then 124 "          ''      (6.02×10^23×124)÷31
                                 ≈2.408×10^24
and molecules are (2.408×10^24×2)
                             ≈4.816×10^24
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The recommended daily allowance (RDA) of the trace metal magnesium is 410 mg/daymg/day for males. Express this quantity in μg/da
Ira Lisetskai [31]

Answer:

410mg/day *\frac{1000 ug}{1 mg}

Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

Explanation:

There are 1000μg in 1 mg and 1000 mg in 1g

1 mg=1000μg

The Recommended daily Amount (RDA) is 410 mg/day of magnesium. Converting 410 mg/day into μg/day

410mg/day *\frac{1000 ug}{1 mg}

It will become 410,000 μg/day

So Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

4 0
3 years ago
Which is not a reason why mass of an atom is expressed in atomic mass units rather than in grams?
Tasya [4]
What are your answer choices? Scientists express the weight in AMU’s so that they can easily think about the weight of the atom. If it is expressed in grams, they’re constantly dealing with a weight that’s around 10^-24 grams, which is hard to deal with.
8 0
4 years ago
Help asap. <br>How many moles are 5.55x10^25 atoms of Mg
LekaFEV [45]

Answer:

\boxed {\boxed {\sf About \ 92.2 \ moles \ of \ Magnesium}}

Explanation:

To convert from atoms to moles, we must Avogadro's number:

  • 6.022*10²³

This number tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, it is atoms of magnesium in 1 mole.

  • 6.022 *10²³ atoms Mg / 1 mol mg

Now, let's set up an expression using:

\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Multiply this by the given number of atoms.

5.55*10^{25} \ atoms \ Mg *\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}

Flip the fraction so the atoms of magnesium can cancel.

5.55*10^{25} \ atoms \ Mg *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23} \ atoms \ Mg}

5.55*10^{25} *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23}}

Multiply and condense this into 1 fraction.

\frac { 5.55*10^{25} \ mol \ Mg }{6.022 * 10^ {23}}

92.1620724 \ mol \ Mg

The original measurement had 3 significant figures, so our answer must have that many as well. For the number we calculated, that is the tenth place. The 6 in the hundredth place tells us to round the 1 to a 2.

92.2 \ mol \ Mg

It is about <u>92.2 moles of magnesium.</u>

3 0
3 years ago
What is the molarity of NaOH if 83.5 mL of NaOH is needed to react with 35.0mL of a 0.275 M solution of H2SO4?
Lostsunrise [7]

Answer:

0.231 mol/L

Explanation:

The first step is to write the balanced equation for this reaction:

H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4}  +2H_{2}O

The second step is to find the number of moles in the acid:

number of moles = volume * concentration

                             = 0.035 L * 0.275 mol/L

                             = 0.009625 mol

The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.

n(sulphuric acid) : n(sodium hydroxide)

          1                :                   2

0.009625 mol    :                   x

x =  0.01925 mol

Fourth step is to calculate the concentration of sodium hydroxide:

concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L

7 0
4 years ago
Does the addition of a catalyst affect the ΔH of reaction?
Semenov [28]

Answer:

no

Explanation:

because its just no lol.

8 0
3 years ago
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