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3 years ago

Hey. Can someone, please help me with the following questions:

1 answer:

4 0

Orbit, natural satellites, international space station, moon

5, naked eye, Mercy, Venus, Mars, Jupiter, Saturn, solar system, 1

I would need to see the choices for this section

1.Stars
2. The Milky Way
3. The sun
4.8 minutes
5. Satellites
6. 100 thousand million
7. Canis Major Dwarf Galaxy
8. 10s of thousands of years

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What else is produced when sodium carbonate decomposes?<br><br> Na2CO3 → Na2O + <br> _________

cricket20 [7]

Answer:

CO2

cardon dioxide is produced

3 0

3 years ago

Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002

marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The $pK_a=4.756$

The value of the dissociation constant = $K_a$

$pK_a=-\log[K_a]$

$K_a=10^{-4.756}=1.754\times 10^{-5}$

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

$HAc\rightleftharpoons H^++Ac^-$

Initially

At equilibrium ;

(c-cα) cα cα

The expression of dissociation constant is given as:

$K_a=\frac{[H^+][Ac^-]}{[HAc]}$

$1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}$

$1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}$

$1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}$

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

$[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M$

The pH of the solution ;

$pH=-\log[H^+]$

$=-\log[0.0001901 M]=3.72$

3 0

4 years ago

Complete and balance the molecular equation, including phases, for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous b

expeople1 [14]

The complete chemical reaction of aqueous Sodium sulfate and aqueous Barium nitrate is

$Na_{2} SO_{4} (aq) + Ba(NO_3)_2(aq) -\ \textgreater \ BaSO_4(s) + 2NaNO_3(aq)$

The right side and the left side of the reaction have equal number of elements, therefore it is balanced.

5 0

3 years ago

Read 2 more answers

Calculate the density of nitrogen gas, in grams per liter, at stp.

lesantik [10]

Standard temperature is 273 K

Standard pressure is 1 atm

We use the ideal gas equation to find out density of nitrogen gas in g/L

Ideal gas equation:

$PV = nRT\\ PV = (\frac{Mass}{Molar mass)}RT\\ P(Molar mass) = (\frac{Mass}{Volume})RT\\ \frac{Mass}{Volume}=\frac{P(molar mass)}{RT} \\ Density = \frac{P(Molar mass)}{RT}$