Balanced chemical equation is - 3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O
Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O
3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.
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Answer:
I think Sammy is right because I'm sure the compound contains ionic bonds
The reaction is properly written as
Mg₃N₂ (s) + 3 H₂O (l) --> 2 NH₃<span> (g) + 3 MgO (s)
Molar mass of Mg</span>₃N₂ = 100.95 g/mol
Molar mass of H₂O = 18 g/mol
Molar mass of MgO = 40.3 g/mol
Moles Mg₃N₂: 3.82/100.95 = 0.0378
Moles H₂O: 7.73/18 = 0.429
Theo H₂O required for available Mg₃N₂: 0.0378*3/1 = 0.1134 mol
Hence, the limiting reactant is Mg₃N₂.
Thus,
Theoretical Yield = 0.0378 mol Mg₃N₂ * 3 mol MgO/Mg₃N₂ * 40.3 g/mol
Theo Yield = 4.57 g
Percent Yield = Actual Yield/Theo Yield * 100
Percent Yield = 3.60 g/4.57 g * 100 =<em> 78.77%</em>
Answer:
Explanation:
Volume is defined as the space occupied by an object or substance irrespective of its state of matter.The conversion used from millimeter to liter is:
1 milliiliter = 0.001 L
Therefore, we can convert the volume of sample from 2.5 ml in liters as follows.
2.5 ml in liters = 2.5ml x 0.001 L/1ml
= 0.0025 L
Thus, we can conclude that the volume of given sample in liter is 0.0025 L
Hope this helps! :)
