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uysha [10]
3 years ago
8

How many moles of atoms are in 6.00 g of 13C?

Chemistry
2 answers:
NARA [144]3 years ago
8 0

There are 0.462 moles of atoms in 6.00 g of carbon-13.

<h2>Further Explanation:</h2><h3>Moles, Atomic mass and Molecular mass  </h3>
  • 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
  • Therefore; molar mass is given as grams per mole of a substance  
  • Hence;

Molar mass = mass of a substance/ Number of moles

     g/mol = g /mole

  • Thus:

M = m/n; where M is the molar mass, m is the mass and n is the number of moles

  • From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.
  • That is; Mass = moles x molar mass
  • To calculate number of moles;

We have; n = m/M

  • Number of moles = Mass of the substance/ Molar mass

In our case;

Mass = 6 g of Carbon-13

Molar mass = 13.0 g/mol

Since; Number of moles = Mass/ molar mass

Thus;

Moles = (6.0 g)/ (13.0 g/mol)

          = 0.462 moles  

Keywords: Moles, Molecular mass, relative atomic mass  

<h3>Learn more about:</h3>
  • Relative atomic mass: brainly.com/question/11096711
  • Moles calculation: brainly.com/question/9709257
  • Molar mass: brainly.com/question/8992028

Level: High school

Subject: Chemistry

Topic: Moles

Sub-topic: Moles, molecular mass and mass of a pure substance

Lyrx [107]3 years ago
4 0

Answer: 0.462 moles

Explanation: 13C indicates an isotope of carbon and its mass number is 13. It means the mass of 1 mol of 13C is 13 gram.

The question asks to calculate the number of atoms present in 6.00 grams of 13C.

To calculate the number of moles we divide the given grams by the mass of 1 mol of the element. The set could be shown easily using dimensional analysis as:

6.00gram(\frac{1mol}{13gram})

= 0.462 moles

So, there will be 0.462 moles of atoms in 6.00 grams of 13C.

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Isotopes are represented with mass numbers. Mass number is the addition of number of proton and number of neutrons.

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