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Softa [21]
3 years ago
12

A horizontal tube carrying hot water has a surface temperature of 355.4 K and an outside diameter

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

The natural convection heat loss is 185.5 W

Explanation:

The equation for convection heat loss is:

Q/t = k*A*(T1-T2)/d

in which: Q/t is the convection heat loss, k is 0.6 W/mK for water, A is the are of the tube which corresponds to (πd^2)/4. d= 25.4 mm or 0.0254 m. The area is 5.06 m2. The difference in temperature is given by the problem: 355.4 K - 294.3 K. d for the convection heat loss is the thickness of the barrier which is 1 m of the length of the pipe.

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Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
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Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

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Explanation :

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b = order with respect to B

Expression for rate law for first observation:

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Expression for rate law for second observation:

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Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

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Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

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