Answer and Explanation:
Find enclosed the Lewis diagrams for ozone (O₃) resonance structures. The diagram shows the two main contributing structures (I and II) with their formal charges.
The formal charge (FC) is determined as follows:
FC= number of valence electrons in free atom - 1/2 (number of bonding electrons) - number of non bonding electrons
The O central atom has the formal charge +1:
FC= 6 - 1/2(6) - 2= +1
The O atom on the right in structure I and on the left in structure II has the formal charge -1:
FC= 6 - 1/2(2) - 6= 6 - 1 - 6 = -1
The O atom on the left in structure I and on the right in structure II has the formal charge 0:
FC= 6- 1/2(4) - 4= 6 - 2 - 4= 0
Answer:
In this case, a neutral atom with 12 protons will have 12 electrons. On the periodic table, the atom with 12 protons is magnesium, which is in group 2 . Therefore, it will most likely lose 2 electrons to have 10 electrons, and form a noble gas configuration. So, magnesium becomes Mg2+ .
To determine this, you can look at the molecular weight of that particular atom which is found on the periodic table. Carbon has a molar mass of 12.01 grams / mole. Sulfur has a molar mass of 32.06 grams / mole. This means one mole of carbon weighs 12.01 grams and one mole of sulfur weighs 32.06 grams. Therefore, one mole of carbon atoms has a smaller mss than one mole of sulfur atoms.
There isn t a 'middle' carbon because there is an even number of them
If the methyl group braches off the 3rd carbon the name is
hexa-3-methyl-3-ene
