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cluponka [151]
2 years ago
15

Someone please help me!​

Mathematics
1 answer:
Natali5045456 [20]2 years ago
4 0

Answer:

number 3

Step-by-step explanation:

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So there are two potential ways you could do this. First just multiple the g=7 into the equation and then add. Or another possibility is to first add the 14g and 3g to get the 17g and then multiply it by the g value and subtract 98. So if we combine the g's and then multiply it by 7, the 17g becomes 17*7=119. So now subtract 98 from 119, 119-98=21. So the overall answer to the expression is 21 when g equals 7.
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A mother is 46 years old and her son is 21 years old in 2021. In what year was the mother six times as old as the son ?
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Functionally important traits in animals tend to vary little from one individual to the next within populations, possibly becaus
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Step-by-step explanation:

Hello!

Given the variable

X:  Ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloth.

The researcher's claim is that the ratio of the SC of the sloths is more variable than in other animal species that are more active.

For more active species the standard deviation of the ratio is σ= 0.09

1)

To calculate the sample standard deviation you have to calculate the sample variance first:

S^2= \frac{1}{n-1} [sumX^2-\frac{(sumX)^2}{n} ]

n=7; ∑X= 8.91; ∑X²= 11.8599

S^2= \frac{1}{6} [11.5899-\frac{(8.91)^2}{7} ]= 0.0287= 0.029

S= √S²= √0.029= 0.169≅ 0.17

The sample standard deviation of the ratio is 0.17

2)

The parameter of interest is the population standard deviation. To calculate a confidence interval for the standard deviation of a population you have to estimate the population variance first. Then calculate the square root of both limits of the interval for the variance to obtain the interval for the standard deviation.

The statistic to use is the Chi-Square and the formula for the interval is:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;\alpha /2}= X^2_{6; 0.025}= 1.2373

X^2_{n-1;1-\alpha /2}= X^2_{6; 0.975}= 14.449

[\frac{6*0.029}{14.449} ;\frac{6*0.029}{1.2373} ]\\

[0.0120; 0.1406]

Using a 95% confidence level you'd expect the interval [0.0120; 0.1406] to include the true value of the population variance of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

Now you have to calculate the square root of each limit:

[√0.0120; √0.1406]

[0.1097; 0.3750]

Using a 95% confidence level you'd expect the interval [0.1097; 0.3750] to include the true value of the population standard deviation of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

3)

As you can see the calculated interval doesn't include the value obtained for the other species.

I hope this helps!

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Answer:

One Solution

Step-by-step explanation:

When she adds 2 to both sides, the equation  is

4x=3x

If you subtract 3x from both sides

x=0

So the equation has exactly one solution

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